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Eduardwww [97]
3 years ago
6

How do you find a parallel aandmd perpendicular line using a graph

Mathematics
1 answer:
yulyashka [42]3 years ago
7 0

The problem asks for the equations of the lines, so you use the information given in the graph to help you write the equations.

The given line has a "rise" of -4 for a "run" of 1, hence a slope of -4/1 = -4. This is the information you need from that line to write the equations of lines through the given point, (4, 3).

(a) The parallel line will have the same slope. You are asked for "an equation", so the simplest is to provide the necessary equation in point-slope form.

The equation of a line with slope m through point (h, k) is ...

... y - k = m(x - h)

For m = -4, (h, k) = (4, 3) your parallel line is ...

... y - 3 = -4(x -4)

(b) The perpendicular line will have a slope that is the negative reciprocal of that of the given line: -1/-4 = 1/4. Using the same point-slope form, your perpendicular line has equation ...

... y - 3 = (1/4)(x - 4)

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Answer:

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Step-by-step explanation:

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PLEASE HELP: The mass of a ball is 128 g. It has a density of 0.5 g/cm³. What is the volume of the ball? Show your work and plac
tiny-mole [99]

Answer:

Part 1) The volume of the ball is 256 cm³

Part 2) The radius of the ball is 3.94 cm

Step-by-step explanation:

Part 1) we know that

The density is equal to divide the mass by the volume

D=m/V

Solve for the volume

The volume is equal to divide the mass by the density

V=m/D

In this problem we have

m=128 g

D=0.5 g/cm³

substitute

V=128/0.5=256 cm³

Part 2) what is the radius of the ball?

we know that

The volume of the sphere (ball) is equal to

V=\frac{4}{3}\pi r^{3}

we have

V=256\ cm^{3}

assume

\pi =3.14

substitute and solve for r

256=\frac{4}{3}(3.14)r^{3}

768=(12.56)r^{3}

r^{3}=768/(12.56)

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7 0
3 years ago
please help! functions and relations. f(x)= square root of x-4. find the inverse of f(x) and it’s domain.
likoan [24]

ANSWER:

\:D.\text{ }f^{-1}\left(x\right)=\left(x+4\right)^2;x\ge-4

STEP-BY-STEP EXPLANATION:

We have the following equation:

f(x)=\sqrt{x}-4

The inverse is the following (we calculate it by replacing f(x) by x and x by f(x)):

\begin{gathered} x=\sqrt{f^{-1}(x)}-4 \\  \\ \sqrt{f^{-1}(x)}=x+4 \\  \\ f^{-1}(x)=(x+4)^2 \end{gathered}

The domain would be the range of the original equation, and it would be the range of values that f(x) could take, which was from -4 to positive infinity, that is, f(x) ≥ -4.

Therefore, the domain is x ≥ -4.

So the correct answer is D.

\:f^{-1}\left(x\right)=\left(x+4\right)^2;x\ge -4

4 0
1 year ago
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steposvetlana [31]
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3 0
3 years ago
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Read 2 more answers
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