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KatRina [158]
3 years ago
9

Suppose f(x) is a function such that for some positive integer n, f has n linearly dependent derivatives. In other words, if f(x

),f′(x),…,f(n−1)(x),f(n)(x) are all linearly dependent functions, then f(x) is expressible in terms of a,xk,eax,sin(ax),cos⁡(ax), and any combination of such functions, where a is a constant and k is a positive integer. Prove this statement

Mathematics
1 answer:
Anon25 [30]3 years ago
6 0

Answer:

See explaination for the prove of the statement.

Step-by-step explanation:

To establish this prove, lets refer back to what we already know.

We know that "If the set of reactions {d1,d2,d3,......dn} in a vector space V over a field f be linearly dependent, then atleast one of the vectors of the set can be expressed as a linear combination of the remaining others.

Please kindly go to attachment for a detailed step by step explaination of the prove.

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a practice field is 250 ft long the game is 40% longer than the practice field of how long is the game ​
Diano4ka-milaya [45]

Answer:

350

Step-by-step explanation:

40% of 250 is 100 (10% of 250 is 25 and 25 times 4 is 100)

250+100 is 350

8 0
3 years ago
What is the rate of change of the linear relationship modeled in the table?
Lisa [10]
The correct answer is 3/2.

Slope = Rate Of Change 

Slope Formula:        y₂ - y₁          5 - 2         3
                               -------------- = ---------- = -----
                                   x₂ - x₁          3 - 1         2

I hope that this helps you!

Btw, ₁ and ₂ are subscripts, they do not have anything to do with the actual working of the problem. 
7 0
3 years ago
See question in attached photo.<br>Answer question 4b and 5c​
sdas [7]

9514 1404 393

Answer:

  4b: 8.6 m/s²; 1.3×10^5 N; 2.1×10^4 N decrease

  5c: -1.6×10^12 J; -1.6×10^12 J

Step-by-step explanation:

<h3>4b</h3>

i) The acceleration due to gravity is inversely proportional to the square of the distance between the objects. The distance to the shuttle is ...

  1 + (5×10^5)/(6.4×10^5) = 69/64 . . . times the radius of the earth

Then the acceleration due to gravity at the height of the space shuttle is about ...

  (10 m/s²)(64/69)² ≈ 8.6 m/s²

__

ii) The weight of the space shuttle at that height is about ...

  F = ma = (15000 kg)(8.6 m/s²) ≈ 1.3×10^5 N

__

iii) The loss of weight will be ...

  ΔF = m(a1 -a0) = (15000 kg)(10 m/s² -8.6 m/s²)

  = 1.5×10^4×1.4 N = 2.1×10^4 N

____

<h3>5c</h3>

i) The gravitational potential energy is given by ...

  U = -GMm/r

where M and m are the mass of the earth and the rocket, respectively.

  U = -(6.67×10^-11)(6.0×10^24)(2.5×10^4)/(6.4×10^6) ≈ -1.6×10^12 J

__

ii) At a height of 3×10^4 m, the denominator in the above expression changes from 6.4×10^6 to 6.43×10^6. This changes the gravitational potential energy by a factor of 6.4/6.43 to -1.6×10^12 J

(Note: we're carrying only 2 significant figures in the result in accordance with the rules for precision in such calculations. The change is noticeable at the level of the 4th significant figure, less than 1/2%.)

4 0
3 years ago
Which of the following points lies on the line y=x?​<br>(-4,4)<br>(2,-2)<br>(-4,-4)<br>-2,2
marshall27 [118]
The answer is (-4,-4) because y has to equal x, the first -4 is the x and the second one is the y
7 0
3 years ago
Subract (8x+6)-(x+4)
NeX [460]

Step-by-step explanation:

8x + 6) - (x + 4)

8x + 6 - (x + 4)

8x + 6 - x - 4

7x + 2

4 0
3 years ago
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