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3 years ago

Classify the following triangle as acute, obtuse, or right.O A. AcuteOB. ObtuseC. Right

Mathematics

1 answer:

makvit [3.9K]3 years ago

4 0

Answer:

right

Step-by-step explanation:

There is a right angle so the triangle is a right triangle

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3 years ago

Find the exact value of sine [2 cosine Superscript negative 1 Baseline (- StartFraction StartRoot 2 EndRoot/2 EndFraction )] = n

Nady [450]

Answer:

$\frac{3\pi}{2}$ .

Step-by-step explanation:

The given expression is

$2\cos^{-1}\left(-\frac{\sqrt{2}}{2}\right)$

It can be rewritten as

$2\cos^{-1}\left(-\frac{1}{\sqrt{2}}\right)$

$2\left [\pi-\cos^{-1}\left(\frac{1}{\sqrt{2}}\right)\right]$ $[\because \cos^{-1}(-x)=\pi-\cos^{-1}(x), x\in [-1,1]]$

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Hence, the exact value of given expression is $\frac{3\pi}{2}$ .

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3 years ago

Suppose P(A)=0.9, P(B)=0.4 and P(B|A)=0.2. What is P(A|B)?

Leokris [45]

The answer is 0.45

------------------------------------

Work Shown:

P(B|A) = P(B and A)/P(A)
0.2 = P(B and A)/0.9
0.2*0.9 = P(B and A)
0.18 = P(B and A)
P(B and A) = 0.18
P(A and B) = 0.18

P(A|B) = P(A and B)/P(B)
P(A|B) = 0.18/0.4
P(A|B) = 0.45

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3 years ago

Classify the following triangle as acute, obtuse, or right.O A. AcuteOB. ObtuseC. Right​

Classify the following triangle as acute, obtuse, or right.O A. AcuteOB. ObtuseC. Right