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melomori [17]
3 years ago
14

Which statement about this function is true?

Mathematics
1 answer:
Mazyrski [523]3 years ago
3 0

Answer:Start studying office equipment module. Learn vocabulary, terms ... Terms in this set (37). Which of these statements is true about preventative maintenance? ... Use the Help function to guide her through the problem. Which tool should Tracy, ..

Step-by-step explanation:

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In country​ A, the vast majority​ (90%) of companies in the chemical industry are ISO 14001 certified. The ISO 14001 is an inter
yan [13]

Answer: a) 0.74, b) (0.70, 0.778)

Step-by-step explanation:

Since we  have given that

Total number of chemical companies n  = 500

Number of companies certified = 370

So, p=\dfrac{370}{500}=0.74

At 95% level of confidence, z = 1.96

So, interval would be

p\pm z\sqrt{\dfrac{p(1-p)}{n}}\\\\=0.74\pm 1.96\sqrt{\dfrac{0.74\times 0.26}{500}}\\\\=0.74\pm 0.038\\\\=(0.74-0.038,0.74+0.038)\\\\=(0.70, 0.778)

Hence, a) 0.74, b) (0.70, 0.778)

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4 years ago
True or false - A risk ratio and an odds ratio are different names for the same concept
aalyn [17]
True would be right
6 0
2 years ago
A rectangle is 24.6 m long and 8.65 m wide what is the area of the retangle
madreJ [45]

Answer:

212.79m

Step-by-step explanation:

A=L×W

A=24.6m×8.65m

A=212.79m

6 0
3 years ago
Which statement proves that F(x) is an exponential function
Alex_Xolod [135]

Answer:

Y=a*b^x

If xponent is a variable

Step-by-step explanation:

4 0
3 years ago
Colby and Jaquan are growing bacteria in an experiment in a laboratory. Colby starts with 50 bacteria in his culture and the num
MakcuM [25]
Here's the general formula for bacteria growth/decay problems

Af = Ai (e^kt)

where: 
Af = Final amount
Ai = Initial amount
k = growth rate constant
<span>t = time

But there's another formula for a doubling problem.
</span>kt = ln(2)

So, Colby (1)
k1A = ln(2) / t
k1A = ln(2) / 2 = 0.34657 per hour.

So, Jaquan (2)
k2A = ln(2) / t
<span>k2A = ln(2) /3 = 0.23105 per hour.
</span>
We need to use the rate of Colby and Jaquan in order to get the final amount in 1 day or 24 hours.

Af1 = 50(e^0.34657(24))
Af1 = 204,800

Af2 = 204,800 = Ai2(e^0.23105(24))
<span>Af2 = 800</span>
6 0
3 years ago
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