What is (-6)^8/(-6)^2
2 answers:
So, you're looking for:
With exponents when you're dividing, you can subtract the exponents when the bases are the same. It works for this.
8-2= 6, So now it's (-6)^6
It's an even exponent, so the answer will be a positive number.
(-6)^6= 46,656
You can even make sure that you're correct by not changing the expression.
So, the answer is 46,656.
With exponents when you're dividing, you can subtract the exponents when the bases are the same. It works for this.
8-2= 6, So now it's (-6)^6
It's an even exponent, so the answer will be a positive number.
(-6)^6= 46,656
You can even make sure that you're correct by not changing the expression.
So, the answer is 46,656.
You might be interested in
Hello.
Given the explicit rule,
×<span> </span>
, 
and r =
,
Your recursive rule is C.
Given the explicit rule,
Your recursive rule is C.
<h3>Answer: 40</h3>
========================================================
Explanation:
The old dimensions of the rectangle were 30 by 15.
The new dimensions are 30+x by 15+x, where x is some positive number.
The new rectangle dimensions multiply to 1000
(30+x)(15+x) = 1000
Use the FOIL rule to expand out the left side like so
(30+x)(15+x) = 1000
450+30x+15x+x^2 = 1000
450+45x+x^2 = 1000
x^2+45x+450
Then lets get everything to one side
x^2+45x+450 = 1000
x^2+45x+450-1000 = 0
x^2+45x-550 = 0
---------------------
From here we use the quadratic formula
Plug in a = 1, b = 45, and c = -550.
Earlier we defined x to be a positive number. This means we ignore x = -55. It makes no sense to add on a negative amount to each dimension.
The only practical answer is x = 10.
So each dimension is increased by 10 feet.
--------------------------
If x = 10, then the old dimensions of 30 by 15 bump up to 30+10 = 40 by 15+10 = 25
Then note how 40*25 = 1000, which helps confirm we have the correct dimensions.
--------------------------
Now go back to the question at hand: we want to find the new width. The old width was 30 feet. The new width is 30+x = 30+10 = 40 feet