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4 years ago

5

Please answer correctly !!!!!!!! Will mark brainliest !!!!!!!!!!!!!

1 answer:

docker41 [41]4 years ago

6 0

Answer:

B

Step-by-step explanation:

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11 points Please answer quick.

ICE Princess25 [194]

Answer:

$\boxed{x^4 + x^2 + x}$

Step-by-step explanation:

$\frac{x^5 - x^4 + x^3 -x^2 + x - 1}{x - 1}$

$= \frac{(x - 1)(x^4 + x^2 + x)}{x - 1}$

$= x^4 + x^2 + x$

.

Happy to help :)

5 0

3 years ago

Please help! I will mark as brainliest. <3

Andrew [12]

<h2>Solving Inequalities</h2><h3>Answer:</h3>

$(-\infty,-8]$

<h3>Step-by-step explanation:</h3>

$-2x +7 \geqslant 23 \\ -2x +7 -7 \geqslant 23 -7 \\ -2x \geqslant 16 \\ \frac{-2x}{-2} \leqslant \frac{16}{-2} \\ x \leqslant -8$

The values of $x$ has to be less than or equal to $8$ so $x \in (-\infty,-8]$

3 0

3 years ago

Subtract rational expression. <br> Show work please.

yan [13]

Given:

$$\frac{x+4}{x-1}-\frac{5}{x^{2}-1}$

To find:

The simplified rational expression by subtraction.

Solution:

Let us factor $x^2-1$ . It can be written as $x^2-1^2$ .

$x^2-1^2=(x-1)(x+1)$ using algebraic identity.

$$\frac{x+4}{x-1}-\frac{5}{x^{2}-1}=\frac{x+4}{x-1}-\frac{5}{(x+1)(x-1)}$

LCM of $x-1,(x+1)(x-1)=(x+1)(x-1)$

Make the denominators same using LCM.

Multiply and divide the first term by (x + 1) to make the denominator same.

$$=\frac{(x+4)(x+1)}{(x-1)(x+1)}-\frac{5}{(x-1)(x+1)}$

Now, denominators are same, you can subtract the fractions.

$$=\frac{(x+4)(x+1)-5}{(x-1)(x+1)}$

Expand $(x+4)(x+1)-5$ .

$$=\frac{x^2+4x+x+4-5}{(x-1)(x+1)}$

$$=\frac{x^{2}+5 x-1}{(x-1)(x+1)}$

$$\frac{x+4}{x-1}-\frac{5}{x^{2}-1}=\frac{x^{2}+5 x-1}{(x-1)(x+1)}$

6 0

3 years ago

Find the lateral area of this square<br> based pyramid.<br> 10 in<br> 5 in

4vir4ik [10]

Answer:

The lateral area of this square pyramid is 100 in^2

Step-by-step explanation:

The lateral area of a polyhedron is the added area of all lateral faces (faces on the side) excluding the bases.

In this case, the lateral sides of the square pyramid are the 4 triangular faces on the sides.

AREA OF ONE TRIANGULAR FACE (given by the formula 1/2 x bh):

1/2 x 10 x 5 = 25

Multiply that by 4 since all 4 triangular faces are similar:

25 x 4 = 100

So the lateral area of the square pyramid is 100 in^2.

Please rate my answer once you know its score! :DD

3 0

3 years ago

What are the domain and range of the function on the graph

Alex Ar [27]

<span>To find the domain, solve the inequality 4 - x > 0. x < 4. Thus, all numbers less than or equal to 4 represent thedomain for this function. When trying to find the domain and range from a graph, the domain is found by looking at the graph from left to right.</span>

5 0

3 years ago