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ratelena [41]
3 years ago
8

What time is 5 3/4 hours after 9:22pm

Mathematics
2 answers:
12345 [234]3 years ago
5 0
2:40 I think, but I may be wrong
Akimi4 [234]3 years ago
4 0
3:07am
45+22=67 which translates to one hour and seven minutes. 5 hours from 9:00 is 2:00 so when you add an hour and seven minutes, you get 3:07
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An algebra test contains 38 problems. Some of the problems are worth 2 points each. The rest of the questions are worth 3 points
Naily [24]

Let 'x' be the problems worth 2 points.

Let 'y' be the problems worth 3 points.

Since, there are 38 total problems.

So, x+y =38 (equation 1)

x = 38-y

Since, a perfect score is 100 points.

So, 2x+3y = 100 (equation 2)

Substituting the value of 'x', we get

2(38-y)+3y=100

76-2y+3y=100

76+y = 100

y = 24

x+y = 38

x = 38-24 = 14

So, 14 problems are worth 2 points and 24 problems are worth 3 points.

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3 years ago
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Combine like terms to create an equivalent expression.<br> -1/2(-3y+10)
Studentka2010 [4]

Answer: 3/2y - 5

Step-by-step explanation:

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3 years ago
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Jose's school has 426 students. His principal has promised the Student Council that their idea will be carried out if they can
evablogger [386]

Answer:

they need 25 more signatures to get their idea carried out

Step-by-step explanation: 25% of 426 is 107 and 107 minus 82 is 25

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3 years ago
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Help! I’ll give extra points:)
Fofino [41]

Answer:

if I'm not wrong I think it's B

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2 years ago
A fluid moves through a tube of length 1 meter and radius r=0.006±0.00025 meters under a pressure p=4⋅105±2000 pascals, at a rat
iris [78.8K]

Answer:

Maximum error for viscosity is 17.14%

Step-by-step explanation:

We know that everything is changing with respect to the time, "r" is changing with respect to the time, and also "p" just "v" will not change with the time according to the information given, so we can find the implicit derivative with respect to the time, and since

n = (\frac{\pi}{8}) (\frac{pr^4}{v})\\

The implicit derivative with respect to the time would be

\frac{dn}{dt}  = \frac{\pi}{8} ( \frac{r^4}{v} \frac{dp}{dt}  + \frac{4pr^3}{v}\frac{dr}{dt} )

If we multiply everything by    dt   we get  

dn  = \frac{\pi}{8} ( \frac{r^4}{v} dp  + \frac{4pr^3}{v}  dr})

Remember that  the error is given by   \frac{dn}{n}   therefore doing some algebra we get that

\frac{dn}{n}  =    4 \frac{dr}{r}  +  \frac{dp}{p}

Since,    r = 0.006   ,   dr = 0.00025 ,  p = 4*105   ,   dp = 2000  we get that

\frac{dn}{n} = 0.1714

Which means that  the maximum error for viscosity is 17.14%.  

5 0
3 years ago
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