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UkoKoshka [18]
4 years ago
5

Use the dot product to find |v| when v= (-8, 2)

Mathematics
1 answer:
8090 [49]4 years ago
7 0

Answer:

It is (8, 2)

Step-by-step explanation:

The lines make it positive

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The pair of variables x=–3, y=8 is the solution to the equation 5x+by=17. Find the coefficient b.
lidiya [134]

Answer:

Step-by-step explanation:

I think I have helped you before with this problem, substitute x and y with -3 and 8 respectively, so 5*(-3)+8b=17, -15+8b=17, 8b=32, divide both sides by 8 and you get b=4

7 0
3 years ago
Question Which ordered pairs are solutions to the equation 2x+10y=12? Select all that apply. Select all that apply: (7,−2) (−5,−
AveGali [126]

Answer:

C and D

Step-by-step explanation:

To determine which pairs are solutions, substitute the coordinates into the left side of the equation and if equal to the right side then they are solutions.

(7, - 2)

2(7) + 10(- 2) = 14 - 20 = - 6 ≠ 12 → (7, - 2) is not a solution

(- 5, - 4)

2(- 5) + 10(- 4) = - 10 - 40 = - 50 ≠ 12 → (- 5, - 4) is not a solution

(4, \frac{2}{5} )

2(4) + 10(\frac{2}{5}) = 8 + 4 = 12 → hence solution

(- 5, \frac{11}{5} )

2(- 5) + 10( \frac{11}{5}) = - 10 + 22 = 12 → hence solution

8 0
3 years ago
What is the net price if a purchase would have come to 1500 at the regular price but the 3% discount applied to this purchase
Julli [10]

<u>Answer:</u>

The net price of the product is $1445.

<u>Solution:</u>

Given, regular price of a product is $1500 and it has a discount at the rate of 3%

We have to find the final price of the product.

We know that, <em>final product of price = regular price – discount price </em>

Final price of product = 1500 – 3% of 1500

Final price of product = 1500-\frac{3}{100} \times 1500

= 1500 – 3 \times 15 = 1500 – 45

Final price = 1455

Hence, the net price of the product is $1445.

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3 years ago
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The answer is b :( hope it helps
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arsen [322]

Answer:

Dai must complete a project. Or, top right hand corner

Step-by-step explanation:

Hope this helps! Stay safe :3

6 0
3 years ago
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