well, we know that θ is in the III Quadrant, where the sine is negative and the cosine is negative as well, or if you wish, where "x" as well as "y" are both negative, now, the hypotenuse or radius of the circle is just a distance amount, so is never negative, so in the equation of cos(θ) = - (2/5), the negative must be the adjacent side, thus


Answer: 16.6
Step-by-step explanation:
a² + b² = c²
7² + b² 18²
49 + b² = 324
Subtract 49 from both sides
b² = 275
√b² = √275
b = 16.583
16.583 ≈ 16.6
Answer:
q/sin105= 15/sin45
Step-by-step explanation: