1 & 4 & 6 are the answers
The answer is 5663588 for your question
If I understand what you are asking, you can use the median as an average since it is not affected by the mean ( median is a measure of center). Since a mean is affected by outliers, it might lower the score if there are very low outliers. But note that if there are outliers way <em>greater </em>it can increase the average. You can use the Inter Quartile Range if shown on a box plot ( measure of variability).
Answer:
24cb 18 hb
Step-by-step explanation:
Let's call C the number of cheese burger sold and H the number of hamburgers.
As the cheeseburger sold are 3/4 of hamburgers, we can represent with the following equation:
C= (3/4)H (equation 1)
The total of burgers sold are the total of cheeseburger plus the total of hamburgers, and the sum 42. The equation representing it is:
C + H = 42
Replacing C by its value of eq. 1:
(3/4)H + H = 42
(3/4)H + (4/4)H = 42
(7/4) H = 42
Dividing both sides by (7/4)
H = 42/(7/4)
H= 42*(4/7)
H= (42/7)*4
H= 6*4
H=24
Then, C is:
C=(3/4)H
C=(3/4)*24
C= 3*24/4
C=72/4
C=18
We can verify it summing C+H
C+H=24+18=42 verified!
