Answer:
10 and 15
Step-by-step explanation:
Let 'x' and 'y' are the numbers we need to find.
x + y = 25 (two numbers whose sum is 25)
(1/x) + (1/y) = 1/6 (the sum of whose reciprocals is 1/6)
The solutions of the this system of equations are the numbers we need to find.
x = 25 - y
1/(25 - y) + 1/y = 1/6 multiply both sides by 6(25-y)y
6y + 6(25-y) = (25-y)y
6y + 150 - 6y = 25y - (y^2)
y^2 - 25y + 150 = 0 quadratic equation has 2 solutions
y1 = 15
y2 = 10
Thus we have
:
First solution: for y = 15, x = 25 - 15 = 10
Second solution: for y = 10, x = 25 - 10 = 15
The first and the second solution are in fact the same one solution we are looking for: the two numbers are 10 and 15 (since the combination 10 and 15 is the same as 15 and 10).
Answer:
Your Answer is ...
x > 3 or x < -7
Step-by-step explanation:
1. x > 3 worked out
|X + 2| > 5
Solve absolute Value
|X + 2| > 5
We know either |X + 2| > 5 or x + 2 < - 5
_________________________________
2. x < -7 Worked out
Hope this Helps!
Take Care!
Answer:
5x2+11x−4
Step-by-step explanation:
=2x2+−4x+8+3x2+15x+−12
Combine Like Terms:
=2x2+−4x+8+3x2+15x+−12
=(2x2+3x2)+(−4x+15x)+(8+−12)
=5x2+11x+−4
have a great weekend <3
Answer:
the answer is .. 2x-10
Step-by-step explanation:
hope this helps!!
