First of all, Rodger must be making some serious cash to have 47 cars. Going back to the question, he can not group the cars in more than 2 ways. He can only group it in 1 way, 47 groups of 1. Pls brainliest
Hint to start out the problem:
eg. For f(4), use the first expression, (x-3)^2 because 4 is greater than 1.
<u><em>Answer:</em></u>
Part a .............> x = 11
Part b .............> k = 57.2
Part c .............> y = 9.2
<u><em>Explanation:</em></u>
The three problems deal with inverse variation between two variables
An inverse variation relation between two variables means that when one of the variables increases, the other will decrease (and vice versa)
<u>Mathematically, an inverse variation relation is represented as follows:</u>

where x and y are the two variables and k is the constant of variation
<u><em>Now, let's check the givens:</em></u>
<u>Part a:</u>
We are given that y = 3 and k = 33
<u>Substitute in the original relation and solve for x as follows:</u>

<u>Part b:</u>
We are given that y = 11 and x = 5.2
<u>Substitute in the original relation and solve for k as follows:</u>

<u>Part c:</u>
We are given that x=7.8 and k=72
<u>Substitute in the original relation and solve for y as follows:</u>
to the nearest tenth
Hope this helps :)
You could start by eliminating wrong answer(s):
(a) 5 is definitely not a factor of the given <span>2xy + 8y − 8x − 32,
(d) x^2 - 4x + 16 (not x2 - 4x + 16) is not a factor (it has no y terms)
On the other hand:
(b) 2 definitely divides evenly into </span>2xy + 8y − 8x − 32: 2(<span>xy + 4y − 4x − 16)
(c) x + 4 divides evenly into both xy + 4y and -(4x + 16):
We get 2(x +4) [y - 4]</span>