Answer:
The outer circle is 16 feet larger than the inner circle (68 - 52).
Step-by-step explanation:
Given that the inner circle circumference is 52 feet, and the distance between the inner and the outer circle is 8 feet, to determine by how many ft is the larger outer circle, the following calculation must be performed:
The radius of a circle is equal to half its diameter. Therefore, the radius of the inner circle is 26 feet. Thus, if the distance between the two circles is 8 feet, the radius of the outer circle is 34 feet (26 + 8). Therefore, the diameter of this circle is 68 feet (34 x 2).
This implies that the outer circle is 16 feet larger than the inner circle (68 - 52).
Ok...I considered it....oh..u want me to answer it...lol..ok
5/6(1/2x + 6) - 3x
5/12x + 30/6 - 3x
5/12x - 36/12x + 5
- 31/12x + 5 <===
Step-by-step explanation:
change the unit
50 km per 1 hour
50 km/h = 50,000 m/ 3600 s = 13.8 m/s
the lorry speed is 13.5 m/s or 0.3 m slower than the limit
I don’t know what the options are please specify
Answer: y=4x-7
Step-by-step explanation:
