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kolbaska11 [484]
3 years ago
15

Willing to Mark brainiest!

Mathematics
2 answers:
dmitriy555 [2]3 years ago
6 0

36 = 4*9  = 2*2 *3*3

Choice C

vesna_86 [32]3 years ago
4 0

The answer is c. 2 * 2 * 3 * 3 = 36

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Write an equation of the line that passes through the origin and
Vanyuwa [196]

Answer:

y = 3x

Step-by-step explanation:

Parallel lines have the same slope, so the slope of this new line will be the same as the given one.

For a line to pass through the origin it needs to have a y intercept of 0, because the origin is the point (0,0).

6 0
3 years ago
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All perfect numbers from 20 to 30
lana [24]

Answer:

There is only one perfect number between 20 to 30 which is 28.

<h3>Explanation:</h3>

The number 28 is a perfect number because its factors are 1, 2, 4, 7, 14 and 28.

7 0
2 years ago
If y varies directly with x, find the value of y when x = 27 for the direct variation with the given information. y = 7 when x =
ElenaW [278]

Given:

y varies directly with x,

It is given that y = 7 when x = -9.

To find:

The value of y when x = 27 for the direct variation.

Solution:

It is given that y varies directly with x, so

y\propto x

y=kx             ...(i)

Where, k is the constant of proportionality.

It is given that y = 7 when x = -9. Putting these values in (i), we get

7=k(-9)

-\dfrac{7}{9}=k

Putting k=-\dfrac{7}{9} in (i), we get

y=-\dfrac{7}{9}x

Putting x=27,  we get

y=-\dfrac{7}{9}(27)

y=-21

Therefore, the required value is y=-21.

3 0
2 years ago
When originally purchased, a vehicle costing $23,000 had an estimated useful life of 8 years and an estimated salvage value of $
earnstyle [38]
The <u>correct answer</u> is:

$5,000.

Explanation:

When it is first purchased, the depreciation expense is calculated using the formula:

\text{Depreciation expense}=\frac{\text{Cost}-\text{Salvage Value}}{\text{Useful Life}}

The cost was $23,000; the salvage value was $3,000; and the useful life was 8 years:

\text{Depreciation Expense}=\frac{23000-3000}{8}=\frac{20000}{8}= \$2500

This means the value of the vehicle depreciates $2500 per year.

After 4 years, the vehicle would depreciate 2500(4) = $10,000.

This makes the new value $23000-$10000 = $13000.

Reevaluating the depreciation expense at this point, we use $13000 for the "cost" (current value), $3000 is still the salvage value, and now the total useful life was 6; we take 4 off of this, since it has already been 4 years:

\text{Depreciation Expense}=\frac{13000-3000}{6-4}=\frac{10000}{2}= \$5000

The depreciation expense in year 5 is $5,000.
6 0
3 years ago
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ASAP________________________________________________________________________
maria [59]

Answer:

c) √121 is the rational number.

Do you know that I am a Indian of age 12

8 0
2 years ago
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