Answer:
B. y= ¼
Step-by-step explanation:
3 + ^4√4y = 4
^4√4y =4-3
^4√4y = 1
^4√4y =^4√1
so, 4y = 1
y = ¼
Step 1) Divide the figure into separate shapes
Large rectangle: 8 x 9
Medium rectangle: 4 x 6
Quarter circle: r = 3
Step 2) Find the area of each shape
Large rectangle: A = 8 x 9 = 72
Medium rectangle: A = 4 x 6 = 24
Quarter circle: A = 1/4 x 3.14 x 3^2 = 7.065 + 3 = 10.065
Step 3) Add the areas together
A = 72 + 24 + 10.065 = 106.065 square millimeters (may need to round to 106.07, but rounding not given in the problem)
Hope this helps! :)
PQRS is an isosceles trapezoid and m < Q=127
so m<Q = m<P =127
answer
127
Josiah and Chana travel at constant and different speeds.
- The point F indicates that after 25 seconds Josiah is 60 meters from the starting line but behind Chana
<h3>How can the what the the point <em>F </em>represent be known?</h3>
Josiah's head start = 10 meters from the start
Josiah's speed = 2 m/s
Chana's speed = 3 m/s
Expressing the distance traveled as an equation, we have;
D = d + s × t
Where;
D = The distance covered
d = The distance from the starting line the runner starts
s = The speed of the runner
t = The time spent running
For Josiah, we have;
D = 10 + 2•t (line <em>a</em>)
For Chana, we have;
D = 0 + 3•t = 3•t (line <em>b</em>)
The above equations are straight line equations.
The point <em>F </em>is on line <em>a</em>, which shows Josiah distance after 25 seconds which is 60 meters. The corresponding point on line <em>b</em>, Chana's distance after 25 minutes is 75 meters.
Therefore;
- The point <em>F </em>indicates that after 25 seconds Josiah is 60 meters from the starting line but behind Chana
Learn more about straight line equations here:
https://brainly.in/question/16254550
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Answer:
less likely
Step-by-step explanation:
Probability is between 0 and 1 so 1 is guaranteed to happen and 0 is guaranteed to not happen
