I hope this helps you
x^2/3 [x^2/3.x^-1/4)^6.1/3.2
x^2/3[x^8-3/12]^4
x^2/3 [x^5/12]^4
x^2/3.x^5/12.4
x^2/3.x^5/3
x^2+5/3
x^7/3
It is not recommended that points be marked with X, let's marked with C(6,6)=(Xc,Yc)
The coordinates of the point C(Xc,Yc) which belongs to the line AB and divides line AB in a ratio m : n = 1 : 2 or m/n=1/2 are get it with following formula
Xc=(Xa+(m/n)Xb) / (1+(m/n)) and Yc=(Ya+(m/n)Yb) / (1+(m/n))
We have A(2,2)=(Xa,Ya) and B(14,14)=(Xb,Yb)
When we replace given coordinates we get
Xc=(2+(1/2)*14) / (1+(1/2)) = (2+7) /(3/2) = 9/(3/2) = (9*2)/3 = 3*2 =6 => Xc=6
Yc=(2+(1/2)*14) / (1+(1/2)) = (2+7) / (3/2) = 9/(3/2) = (9*2)/3 = 3*2 =6 => Yc=6
C(Xc,Yc)=(6,6)
Good luck!!!
The probability of an event is considered fair when the probability of the event happening is equally likely.
Thus, the way <span>each vote should be counted so that the outcome is fair is "</span><span>The freshman votes count as 1 vote, the sophomore as 1.14 votes, the juniors as 1.45 votes, and the seniors as 1.23 votes.</span>"
Answer:

Step-by-step explanation:
Factoring out y + 8:

Answer:
120
Step-by-step explanation:
We are given that the function for the number of students enrolled in a new course is
.
It is asked to find the average increase in the number of students enrolled per hour between 2 to 4 hours.
We know that the average rate of change is given by,
,
where f(x)-f(a) is the change in the function as the input value (x-a) changes.
Now, the number of students enrolled at 4 = f(4) =
= 255 and the number of students enrolled at 2 = f(2) =
= 15
So, the average increase
=
=
= 120.
Hence, the average increase in the number of students enrolled is 120.