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prohojiy [21]
4 years ago
11

Explain how to regroup 43 ones as tens and ones

Mathematics
1 answer:
zepelin [54]4 years ago
6 0
The number 43 has 4 tens and 3 ones.

Now we have 43 ones given, in order to regroup them, we need to group 4 rows of 10 each and 3 rows of 1 each.

By this, we will be having:
4 rows of 10 each = 4*10 = 40
3 rows of 1 each = 3*1 = 3
which is the needed 43.
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Cual es el resultado?
Korolek [52]
I hope this helps you


x^2/3 [x^2/3.x^-1/4)^6.1/3.2


x^2/3[x^8-3/12]^4


x^2/3 [x^5/12]^4


x^2/3.x^5/12.4


x^2/3.x^5/3


x^2+5/3


x^7/3
5 0
3 years ago
Line AB is a directed segment with endpoints A(2,2) and B(14,14). In two or more complete sentences, explain how you would verif
Kisachek [45]

It is not recommended that points be marked with X, let's marked with C(6,6)=(Xc,Yc)

The coordinates of the point C(Xc,Yc) which belongs to the line AB and divides line AB in a ratio m : n = 1 : 2 or m/n=1/2 are get it with following formula

Xc=(Xa+(m/n)Xb) / (1+(m/n)) and Yc=(Ya+(m/n)Yb) / (1+(m/n))

We have A(2,2)=(Xa,Ya) and B(14,14)=(Xb,Yb)

When we replace given coordinates we get

Xc=(2+(1/2)*14) / (1+(1/2)) = (2+7) /(3/2) = 9/(3/2) = (9*2)/3 = 3*2 =6 => Xc=6

Yc=(2+(1/2)*14) / (1+(1/2)) = (2+7) / (3/2) = 9/(3/2) = (9*2)/3 = 3*2 =6 => Yc=6

C(Xc,Yc)=(6,6)

Good luck!!!



4 0
3 years ago
A high school is conducting a vote to see which class (freshman, sophomore, junior, or senior) can go to see a play performance.
Lady_Fox [76]
The probability of an event is considered fair when the probability of the event happening is equally likely.

Thus, the way <span>each vote should be counted so that the outcome is fair is "</span><span>The freshman votes count as 1 vote, the sophomore as 1.14 votes, the juniors as 1.45 votes, and the seniors as 1.23 votes.</span>"
6 0
3 years ago
Rewrite the expression by factoring out (y+8).<br> 5(y+8) - 7y (y + 8)<br> 0<br> X<br> 5
andrew-mc [135]

Answer:

(5-7y)(y+8)

Step-by-step explanation:

Factoring out y + 8:

5(y+8) - 7y (y + 8)=(5-7y)(y+8)

6 0
2 years ago
HELP!!!
ella [17]

Answer:

120

Step-by-step explanation:

We are given that the function for the number of students enrolled in a new course is f(x) = 4^{x}-1.

It is asked to find the average increase in the number of students enrolled per hour between 2 to 4 hours.

We know that the average rate of change is given by,

A = \frac{f(x)-f(a)}{x-a},

where f(x)-f(a) is the change in the function as the input value (x-a) changes.

Now, the number of students enrolled at 4 = f(4) = f(x) = 4^{4}-1 = 255 and the number of students enrolled at 2 = f(2) = f(x) = 4^{2}-1 = 15

So, the average increase A=\frac{f(4)-f(2)}{4-2} = A=\frac{255-15}{4-2} = A=\frac{240}{2} = 120.

Hence, the average increase in the number of students enrolled is 120.

3 0
4 years ago
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