Answer:
mews jh
Step-by-step explanation:
Use Pythagorean theorem:
9i-j = sqrt (9^2 - 1^2) = sqrt(81-1) = sqrt80
now divide both terms in V by that:
u = 9/sqrt(80)i - 1/sqrt(80)j
see attached picture:
The answer to this question will be A
3/2 We look for a number that goes into both 9 and 6 without leaving a remainder, and that number is 3
Answer:
the pics too small I cant read itttt
Step-by-step explanation:
make it bigger and I can do ittt