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4 years ago

If I equals PRT which equation is equivalent to T

Mathematics

1 answer:

snow_lady [41]4 years ago

7 0

I = P · R · T
Divide both sides by P·R
I/(P·R) = T

Answer: $\frac{I}{PR} = T$

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It says to find the area of the figure but I have no idea what to do

Westkost [7]

2.5 is also on the top and try multiplying 2.5 and 10

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3 years ago

Can somebody help me out with the question

Evgen [1.6K]

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Step-by-step explanation:

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3 years ago

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Porky the pig weighs 1,125 lbs. Less than Kobe the Cow. After each gains 50lbs. Kobe the Cow will weigh ten times as much as por

Papessa [141]

Answer:

Step-by-step explanation:

Let x represent the initial weight of Porky the pig.

Porky the pig weighs 1,125 lbs less than Kobe the Cow. This means that the initial weight of Kobe the cow is

x + 1125

After each gains 50lbs. Kobe the Cow will weigh ten times as much as porky the pig. This means that

(x + 1125) + 50 = 10(x + 50)

x + 1125 + 50 = 10x + 500

10x - x = 1125 + 50 - 500

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x = 675/9

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Porky's current weight is

75 + 50 = 125 lbs

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(75 + 1125) + 50

= 1250 lbs

4 0

3 years ago

On a coordinate plane, rhombus W X Y Z is shown. Point W is at (7, 2), point X is at (5, negative 1), point Y is at (3, 2), and

Otrada [13]

Answer:

$P = 4\sqrt{13}$

Step-by-step explanation:

Given

$W = (7, 2)$

$X = (5, -1)$

$Y = (3, 2)$

$Z =(5, 5)$

Required

The perimeter

To do this, we first calculate the side lengths using distance formula

$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2$

So, we have:

$WX = \sqrt{(5- 7)^2 + (-1 - 2)^2$

$WX = \sqrt{13}$

$XY = \sqrt{(3-5)^2 + (2--1)^2}$

$XY = \sqrt{13}$

$YZ = \sqrt{(5-3)^2 + (5-2)^2}$

$YZ = \sqrt{13}$

$ZW = \sqrt{(7 - 5)^2 + (2 - 5)^2}$

$ZW = \sqrt{13}$

The perimeter is:

$P = WX + XY + YZ + ZW$

$P = \sqrt{13}+\sqrt{13}+\sqrt{13}+\sqrt{13}$

$P = 4\sqrt{13}$

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3 years ago

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Create an exponential function that starts at 650 and increases by 12% us the form f(x) = p (1=r)^x

ololo11 [35]

F(x)= 650(1+.12)^x

f(x) = 650(1.12)^x

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3 years ago