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Luba_88 [7]
3 years ago
9

Does 28,53,45 make a right triangle

Mathematics
1 answer:
Arada [10]3 years ago
7 0

Answer:

yesh it does

Step-by-step explanation:

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What is the divisibility rule(s) for 93?
My name is Ann [436]
It is prime, it can't be divided by anything, but itself and one.
7 0
3 years ago
Read 2 more answers
Dominic runs a farm stand that sells peaches and grapes. Yesterday Dominic sold 34 pounds of peaches and 45 pounds of grapes for
scoray [572]

Answer:

34x + 45y = 192.25

47x + 16y = 208

Step-by-step explanation:

Let x stand for peaches.

Let y stand for grapes.

Since we know that yesterday he sold 35 pounds of peaches ( x ) and 45 pounds of grapes ( y ) for $192.25, we can create an equation to represent this using two variables; peaches and grapes.

We can do the same thing with the amount of peaches and grapes he sold today. Once we make this equation, we will have two equations to make the system of equations to solve for x and y.

6 0
2 years ago
The ratio of snails to fish in the fishtank is 2:5
Elina [12.6K]
There are 6 snails and 5 fish.
6:15, because
2:5
2+5=7
21/7=3
2:5(3)= 6:15
7 0
2 years ago
Solve for qqq. 3\left(q+\dfrac43\right) = 23(q+ 3 4 ​ )=2<br>pls answer this
enyata [817]

Answer:

<h2>19/3</h2>

Step-by-step explanation:

Given the expression 3\left(q+\dfrac43\right) = 23, we are to find the value of q;

3\left(q+\dfrac43\right) = 23\\on\ expansion\\\\3q + 4/3(3) = 23\\\\3q+4 = 23\\\\subtract \ 4\ from \ both\ sides \ of \ the \ equation\\\\3q+4-4 = 23-4\\\\3q = 19\\\\Diviide \both\ sides \ by \ 3\\\\3q/3 = 19/3\\\\q = 19/3

Hence the value of q is 19/3

6 0
3 years ago
&lt;
Alik [6]

Answer:

2cm of Rainfall

Step-by-step explanation:

When the no. of mosquitoes is the highest the slope of graph will be zero

so if we differentiate this function and equate to zero we can find the rainfall amount that gives maximum number of mosquitoes in centimetres.

m(x)= -x²+4x

differentiate

d(x)/d(m(x))= -2x+4

equate to zero

-2x+4=0

2x=4

x=2

answer: 2 cm of rain

6 0
3 years ago
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