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attashe74 [19]
3 years ago
11

Is Retinoblastoma codominant?

Biology
1 answer:
sashaice [31]3 years ago
5 0
The correct answer is no.
<span>The development of retinoblastoma occurs as a consequence of mutation of genes RB1 or MYCN. Those mutations occur in the early stages of fetal development and affect the way in which cells grow and develop within the body. The more common is the defective RB1 gene that can be inherited from either parent. The expression of the RB1 allele is autosomal dominant.</span>
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Its dark enegry

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3 0
3 years ago
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Red–green color blindness is an X-linked recessive trait in humans. Polydactyly (extra fingers and toes) is an autosomal dominan
Tamiku [17]

Answer:

The girls with polydactyly  color-blind and is 1/8, the boys with normal fingers and color vision is 1/8.

Explanation:

X - linked recessive trait may be defined as the trait that are normally passes down from mother to son. Males have high chances since they have only one X chromosme. The female should have both X chromosome affected to express the trait. Autosomal dominant trait express the trait in both the homozygous dominant and heterozygous condition.

The red - green color blinded male with polydactylous is married with female that have normal color vision and normal toes and finger. With the help of pedigree chart and probability,the outcome of their children with specific phenotype can be calculated.

Martha is normal for poldactyly and contains recessive trait for polydactyly. She is a carrier for the color blindness as his father is affected by the disease. Bill is affected by the color blindness and heterozygous for the polydactyly trait. The marriage between marry and bill have the children with  1/8 proportion of the girls can be color bind and shows polydactyly {1/4 ( girls with color blindness) × 1/2 ( the probability of polydactyly}. 1/8 proportion of the boys with normal vision and normal toes and finger {1/4 (boys are normal) × 1/2 ( the probability of normal toes and finger}.

5 0
3 years ago
Which activity occurs in the process of replication?
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3 years ago
Suppose a population is carrying a condition controlled by two alleles: R (dominant) and r (recessive). Only homozygous individu
storchak [24]

The answer is; A.

If r allele is found in 15% of the population, then the frequency of the allele is;

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Therefore; R + r = 1; R + 0.15 = 1; R = 1-0.15 = 0.85

RR = 0.85*0.85 = 0.7225

In percentage = 0.7225*100 = 72.25


6 0
3 years ago
Read 2 more answers
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