<h3>
Answer: Choice A. 82 websites per year</h3>
=============================================================
How I got that answer:
We have gone from 54 websites to 793 websites. This is a change of 793-54 = 739 new websites. This is over a timespan of 2004-1995 = 9 years.
Since we have 739 new websites over the course of 9 years, this means the rate of change is 739/9 = 82.1111... where the '1's go on forever. Rounding to the nearest whole number gets us roughly 82 websites a year.
----------
You could use the slope formula to get the job done. This is because the slope represents the rise over run
slope = rise/run
The rise is how much the number of websites have gone up or down. The run is the amount of time that has passed by. So slope = rise/run = 739/9 = 82.111...
In a more written out way, the steps would be
slope = rise/run
slope = (y2-y1)/(x2-x1)
slope = (793 - 54)/(2004 - 1995)
slope = 739/9
slope = 82.111....
Answer:
(9159 / 7 = 1308.429)
Step-by-step explanation:
Simply multiply the last digit by 2 and then subtract the product from the remaining digits.
If that difference is divisible by 7, then 9159 is divisible by 7.
The last digit in 9159 is 9 and the remaining digits are 915. Thus, the math to determine if 9159 is divisible by 7 using our alternate method is:
915 - (9 x 2) = 897
Since 897 is not divisible by 7, 9159 is also not divisible by 7.
Therefore, the answer to "Is 9159 Divisible By 7?" is no.
(9159 / 7 = 1308.429)
To solve 7-2a-5-14=-2+3a :
1) combine like terms: 7-19 - 2a = -2 + 3a, and then -10 = 5a
2) solve this equation for a: a = -10/5 = -2.
The solution of 7-2a-5-14=-2+3a is a = -2.
Answer:
Rs 38,640
Step-by-step explanation:
<u>Pay attention:</u>
The principle (p) : Rs 42,000
Rate of interest (r) : 8%
Time (n) : 1 years
Exact Amount (a) : P(1-R/100)^n
Value:
A = 42,000(1 - 8/100)^1
A = 42,000(1 - 2/25)
A = (42,000 * 23)/25
A = 1,680 * 23
A = Rs 38,640
Answer:
m = -5.3
Step-by-step explanation:
-39.75 = 7.5m
Divide both sides by 7.5 to get m alone
-39.75/7.5 = 7.5m/7.5
-5.3 = m
Hope this helps:)
