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zloy xaker [14]
3 years ago
8

Which Pythagorean identity is correct?

Mathematics
2 answers:
Alla [95]3 years ago
5 0

Answer:

Option 2:

tangent squared (theta) + 1 = secant squared (theta)

Step-by-step explanation:

1 + tan²X

1 + sin²X/cos²X

(cos²X + sin²X)/cos²X

1/cos²X

sec²X

navik [9.2K]3 years ago
5 0

Answer:

tangent squared (theta) + 1 = secant squared (theta)

e2020

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An airplane has 100 seats for passengers. Assume that the probability that a person holding a ticket appears for the flight is 0
zmey [24]

Answer:

96.33% probability that everyone who appears for the flight will get a seat

Step-by-step explanation:

I am going to use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 105, p = 0.9

So

\mu = E(X) = np = 105*0.9 = 94.5

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{105*0.9*0.1} = 3.07

What is the probability that everyone who appears for the flight will get a seat

100 or less people appearing to the flight, which is the pvalue of Z when X = 100. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{100 - 94.5}{3.07}

Z = 1.79

Z = 1.79 has a pvalue of 0.9633

96.33% probability that everyone who appears for the flight will get a seat

7 0
2 years ago
At the North campus of a performing arts school 30% of students are music majors at the South campus 80% of the students are mus
OLEGan [10]

Answer:

It should be option B

Step-by-step explanation:

4 0
3 years ago
Complete the Square and express the quadratic as a square.
Shtirlitz [24]

Answer:

C

Step-by-step explanation:

x² - 6x + 13 = 0

x² - 2(x)(3) + 3² - 3² + 13 = 0

(x - 3)² = -4

6 0
3 years ago
Is 31/50 greater than 1/2
KengaRu [80]
Yes 31/50 is greater than 1/2
5 0
3 years ago
Read 2 more answers
What are the postulates for congruent triangles
Delvig [45]

Hi there!

There are 5 ways to find if two triangles are congruent :

SSS, SAS, ASA, AAS & HL

<u>1. SSS (Side, Side, Side)</u>

Means that we have two triangles with 3 sides equal.

⇒ If 3 sides of one triangle are equal to 3 sides of another triangle, the triangles are congruent.

<u>2. SAS (Side, Angle, Side)</u>

Means that we have two triangles where we know 2 sides and the included angle are equal.

⇒ If 2 sides and the includent angle of one triangle are equal to the corresponding sides and angle of another triangle, the triangles are congruent.

<u>3. ASA (Angle, Side, Angle)</u>

Means that we have two triangles where we know 2 angles and the included side are equal.

⇒ If 2 angles and the included side of one triangle are equal to the corresponding angles and side of another triangle, the triangles are congruent.

<u>4. AAS (Angle, Angle, Side)</u>

Means thant we have two triangles where we know 2 angles and the non-included side are equal.

⇒ If 2 angles and the non-included side of one triangle are equal to the coresponding angles and side of another triangle, the triangles are congruent.

<u>5. HL (Hypotenuse, leg)</u>

** This one only applies to <em><u>right-angled triangles</u></em>.**

Hypotenuse: The longest side of a right-angled triangle.

Legs: The other 2 sides of the right-angled triangle.

Means we have two right-angled triangles with the same length of hypotenuse and the same length for one of the other 2 legs (it doesn't matter which leg since the triangles could be rotated).

⇒ If the hypotenuse and one leg of one right-angled triangles are equal to the corresponding hypotenuse and leg of another right-angled triangles, the two triangles are congruent.


There you go! I really hope this helped, if there's anything just let me know! :)

7 0
3 years ago
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