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Vika [28.1K]
2 years ago
7

Are you able to see this question?​

Mathematics
1 answer:
Finger [1]2 years ago
7 0

Answer:

hot dogs: 18

packs of hot dogs: 3

packs of hot dogs buns: 2

Step-by-step explanation:

hope this helps

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Evaluate x - 7 for x = 14.
Aleksandr-060686 [28]

Answer:

x=21

Step-by-step explanation:

x-7=14

add  7 to both sides

x=21

8 0
3 years ago
Solve 4(a-3) = 22 <br> solve 5(x -6) = 65<br><br> with explanation, please <br> giving 20 points
DaniilM [7]

Step-by-step explanation:

4(a-3)=22

a-3=4-22

a-3=18

a=18+3

a=21

5(x-6)=65

x-6=65-5

x-6=60

×=60+6

x=66

hope it will help u...............

5 0
3 years ago
Read 2 more answers
What is 1.35 as a fraction
IgorC [24]
It is 1\frac{7}{20} or as an improper fraction it would be \frac{27}{20}
7 0
2 years ago
Read 2 more answers
If g (x) = 1/x then [g (x+h) - g (x)] /h
lys-0071 [83]

Answer:

\dfrac{-1}{x(x+h)}, h\ne 0

Step-by-step explanation:

If g(x) = \dfrac{1}{x}, then g(x+h) = \dfrac{1}{x+h}. It follows that

  \begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \cdot [g(x+h) - g(x)] \\&= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\end{aligned}

Technically we are done, but some more simplification can be made. We can get a common denominator between 1/(x+h) and 1/x.

  \begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\\&=\frac{1}{h} \left(\frac{x}{x(x+h)} - \frac{x+h}{x(x+h)} \right) \\ &=\frac{1}{h} \left(\frac{x-(x+h)}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{x-x-h}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{-h}{x(x+h)}\right) \end{aligned}

Now we can cancel the h in the numerator and denominator under the assumption that h is not 0.

  = \dfrac{-1}{x(x+h)}, h\ne 0

5 0
3 years ago
There were 60 seventh grade students who signed up for soccer tryouts last year. This year, 48 seventh graders signed up for try
Lubov Fominskaja [6]

Answer:

20%

Step-by-step explanation:

(60 - 48) / 60 = 0.2    (20%)

3 0
3 years ago
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