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3 years ago

8

Sophie bought art supplies at a craft store. She bought paper for $3.00 and four brushes. The brushes all cost the same amount.

Write an expression that represents her total

2 answers:

yuradex [85]3 years ago

7 0

The answer is 4x +3. Hope you have a great day

yulyashka [42]3 years ago

5 0

Answer:

4x+3

Step-by-step explanation:

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How to work out the equation

sveta [45]

first, distribute -6 to (2b + 1), giving you -12b - 6, and then on the another side of the equation, distribute -2 to (5 + 4b) giving you, -10 - 8b. now we need to put our coefficients on one side so we will add 8b to each side of the equation, giving us -6 = -10 - 8b + 12b, then we will add 10 to both sides of the equation giving us, 10 -6 = -8b +12b, this gives u 4 = 4b. then, you would solve for b, which equals 1.

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3 years ago

Simplify to a single power of 4:<br> 4^7/4^6

Temka [501]

Step-by-step explanation:

$\frac{ {4}^{7} }{ {4}^{6} }$

= 4

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4 0

2 years ago

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What is the surface area of the rectangular prism formed from this net?

Reika [66]

E is the answer to this question

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2 years ago

What is the solution of-+-<?<br> 1 1 1<br> X35

sergij07 [2.7K]

Answer:

A. $-\frac{15}{2} < x< 0$

Step-by-step explanation:

Multiply to remove the fraction, then set equal to 0 and solve.

3 0

3 years ago

construct a 90% confidence interval of the population proportion using the giver information x=74 n=150

FrozenT [24]

Answer:

The 90% confidence interval of the population proportion is (0.43, 0.56).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population proportion <em>p</em> is:

$CI=\hat p\pm z_{\alpha/2}\ \sqrt{\frac{\hat p(1-\hat p)}{n}}$

The information provided is:

<em>X</em> = 74

<em>n</em> = 150

Confidence level = 90%

Compute the value of sample proportion as follows:

$\hat p=\frac{X}{n}=\frac{74}{150}=0.493$

Compute the critical value of <em>z</em> for 90% confidence level as follows:

$z_{\alpha/2}=z_{0.10/2}=z_{0.05}=1.645$

*Use a <em>z</em>-table.

Compute the 90% confidence interval of the population proportion as follows:

$CI=\hat p\pm z_{\alpha/2}\ \sqrt{\frac{\hat p(1-\hat p)}{n}}$

$=0.493\pm 1.645\times \sqrt{\frac{0.493(1-0.493)}{150}}\\\\=0.493\pm 0.0672\\\\=(0.4258,\ 0.5602)\\\\\approx (0.43,\ 0.56)$

Thus, the 90% confidence interval of the population proportion is (0.43, 0.56).

3 0

3 years ago