Answer:
function dataSamples=AdjustMinValue(numberSamples, userSamples, minValue)
dataSamples=userSamples;
%for loop
for i=1:numberSamples
%checking if dataSamples value at index,i
%is less than minValue
if dataSamples(i)<minValue
%set double of dataSamples value
dataSamples(i)= 2*dataSamples(i);
end
end
end
Explanation:
The given code is in MATLAB.
Data sharing, maintaining security
<u>Explanation:</u>
Kristian is a cybersecurity professional. She is writing a book called The Door Toward Cybersecurity. Organizations should avoid any data <u>sharing or exchange</u> while servers are transmitting information. This will help organizations keep the information intact and maintain <u>security.</u> If any info or data shared when the servers are transmitting the info, then it may lead to the loss of security, and the information gets leaked. So it must be avoided to share while transmission of info using the servers.
Answer:
The receiver will not detect the error.
Explanation:
The byte sent by transmitter: 10101010
The byte received by receiver due to channel noise: 10011010
If you see the bold part of the both sent and received bytes you can see that the number of bits changed is 2.
The two communicating devices are using a single-bit even parity check. Here there are two changed bits so this error will not be detected as this single bit even parity check scheme has a limit and it detects the error when the value of changed bit is odd but here it is even.
This parity scheme basically works well with the odd number of bit errors.