Answer:
Answer is Below
Explanation:
According to resourcegate.net, A codon consisting of a single base could only code for 4 amino acids, a length of two bases for 16 (4x4), and of three bases for 64 (4x4x4). Given that tRNAs have to interact via their anticodons with the mRNA, we have an upper limit for the codon length.
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Answer:
The Lungs. The lungs play a mandatory role in the excretory system. Your lungs remove the carbon dioxide built up in your blood using specialized cells known as alveoli. Your lungs process the molecules into gas and when you breathe, the gas is ejected from your body.
Explanation:
Answer: The correct answer is option B) a scar and wolf's social status.
The acquired traits can be defined as the traits, which are only influenced by the environment of the organism. The acquired trait cannot be passed down to the offspring, as they are not genetically determined. A scar and the social status of any organism is dependent on the behavior of the organism to the environment, no genes code for both of these characters. So, scars and Wolf's social status is an acquired trait.
Explanation:
Answer:
Uno de los progenitores es heterocigoto para color naranja (Nn) y el otro parental es homocigoto recesivo para gris (nn). Al haber una cruza entre un homocigoto recesivo y un heterocigoto, la 50% de la progenie expresa color naranja (Nn), mientras que el otro 50% expresa color gris (nn).
Explanation:
<u>Datos disponibles:</u>
- Cruce entre peces naranjas y peces grises
- 50% de la F1 son peces grises
- Naranja dominante sobre gris
Podemos nombrar el alelo dominante para color naranja <em>N</em>, y al alelo recesivo para color gris <em>n</em>.
Para que en un cruce entre dos fenotipos distintos, el 50% de la primer camada exprese uno de estos fenotipos, entonces uno de los parentales debe ser heterocigoto, mientras que el otro parental debe ser homocigoto recesivo. De esta forma 50% de la primera generación expresara uno de los fenotipos, mientras que el otro 50% expresará el otro fenotipo.
Supongamos que uno de los parentales lleva el genotipo <em>Nn</em>, y el otro parental es <em>nn</em>.
Cruce:
Parental) Nn x nn
Gametas) N n n n
Fenotipos) Naranja Gris
Cuadro de Punnett) N n
n Nn nn
n Nn nn
F1) 2/4 = 1/2 = 50% de la progenie tendrá genotipo heterocigoto, Nn
2/4 = 1/2 = 50% de la progenie tendrá genotipo homocigota recesivo,
nn
50% de la progenie será color naranja (Nn)
50% de la progenie será color gris (nn)
Answer:
18 ATP.
Explanation:
Total 18 ATP are produced because 9 FADH2 are converted into 9 ATP molecules and the earlier 9 ATP molecules are already present in the first b-oxidation process. The first Krebs cycle produces 27 NADH, 9 FADH2 and 9 ATP while on the other hand, the second Krebs cycle produces 9 ATP molecules from 9 FADH2 so total it produces 18 ATP molecules.
