0.8888888 = 8/9
2.8888888 = 26/9
-2.888888 = -26/9
Answer: See explanation
Step-by-step explanation:
Your question isn't well written but I saw an identical question:
A bookshelf is 42 inches long. Each book is 1 1/4 inches wide. How many books will fit on the shelf?
For us to solve this, we would divide the length of the bookshelf by the width of each book. This would be:
= 42 ÷ 1 1/4
= 42 ÷ 5/4
= 42 × 4/5
= 33 3/5
Therefore, the number of books that will fit on the shelf is 33.
- 38.79
- 3053.63
- 904.78
- 2544.69
- 226.19
- 402.12
- 1072.33
- 1526.81
- 28.73
- 113.1
- 3801.33
- 268.08
- 2094.4
- 75.4
- 94.25
- 37.7
- 1884.96
- 2065.24
- 19861.7
- 1385.44
- 287.98
- 4.19
- 3619.11
- 113.1
- 50.27
I did this really quick so I hope all the answers are right, and double check them if you have time just in case
Let h represent the height of the trapezoid, the perpendicular distance between AB and DC. Then the area of the trapezoid is
Area = (1/2)(AB + DC)·h
We are given a relationship between AB and DC, so we can write
Area = (1/2)(AB + AB/4)·h = (5/8)AB·h
The given dimensions let us determine the area of ∆BCE to be
Area ∆BCE = (1/2)(5 cm)(12 cm) = 30 cm²
The total area of the trapezoid is also the sum of the areas ...
Area = Area ∆BCE + Area ∆ABE + Area ∆DCE
Since AE = 1/3(AD), the perpendicular distance from E to AB will be h/3. The areas of the two smaller triangles can be computed as
Area ∆ABE = (1/2)(AB)·h/3 = (1/6)AB·h
Area ∆DCE = (1/2)(DC)·(2/3)h = (1/2)(AB/4)·(2/3)h = (1/12)AB·h
Putting all of the above into the equation for the total area of the trapezoid, we have
Area = (5/8)AB·h = 30 cm² + (1/6)AB·h + (1/12)AB·h
(5/8 -1/6 -1/12)AB·h = 30 cm²
AB·h = (30 cm²)/(3/8) = 80 cm²
Then the area of the trapezoid is
Area = (5/8)AB·h = (5/8)·80 cm² = 50 cm²
7200
You have to multiply 20×60 to get 1200 which is the area of one pennant multiply that by six and you get 7200 which is the area of six pennant
