Question

The two congruent sides of an isosceles triangle are each 2 inches more than three times the base. Find the length of the two congruent sides of the triangle if it’s perimeter is 88 inches.

Answer 1

Answer:

So the congruent sides measures 38 inches each one.

Step-by-step explanation:

Is important to remember that the perimeter of a triangle is equal to the sum of all its sides.

Some notation

Base=x

Each of the two congruent sides of an isosceles triangle are 2 inches more than three times the base

If we express the congruent sides with the letter c and we express this in terms of x  we have:

c=3x+2

The perimeter of the triangle is given 88 inches

Now we can use formula for perimeter of triangle to solve for x

(Congruent side)+(Congruent side)+(base)=perimeter

(3x+2)+(3x+2)+(x)=88

3x+2+3x+2+x=88  

7x+4=88

We subtract 4 on both sides

7x=84, and if we divide both sides by 7 we got:

x=12, that represent the length of the base.

The base measures 12 inches

Both sides are equal to 3x+2 . If we replace the value of x obtained we have:

c=3(12)+2=38

So the congruent sides measures 38 inches each one.