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4 years ago

480 calories in an 9 ounce serving. What is the unit rate in simplest form?

Mathematics

1 answer:

Bumek [7]4 years ago

3 0

Answer:

53.334 calories per ounce

Step-by-step explanation:

480 calories in 9 ounce serving

480 divided by 9

480 divided by 9 is 53.33333333

round up to the nearest thousandths

answer is 53.334 calories per ounce

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A mountain road is 5 miles long and gains elevation at a constant rate. After 2 miles, the elevation is 5500 feet above sea leve

Mama L [17]

The answer is b ok bro it is 7x plus 8

7 0

1 year ago

A dairy farmer decides to sell three fifth of her 500 cows. How many cows will she be left with after the deal is complete?

seraphim [82]

Answer is 200 cows
Step by step
She is selling 3/5 of 500
Multiply across 3/5 x 500
1500/5 divide to get 300 sold
Now 500-300 sold = 200 cows left
Problem solved

3 0

2 years ago

For accounting purposes, the value of assets (land, buildings, equipment) in a business are depreciated at a set rate per year.

Fantom [35]

Answer:

V(0)=$537,000

b=0.83

t=9

v (9)=100,386.92

Value after 9 years of depreciation at 17% per year

b = 1- r

b = 1 - 17% b = 0.83

Step-by-step explanation:

V (t)=V(0) (b)^t

V (t) future value ?

Vo present value $537,000

b=0.83

T time =9 years

V (9)=537,000×(0.83)^(9)

v (9)=100,386.92

Value after 9 years of depreciation at 17% per year

b = 1- r

b = 1 - 17% b = 0.83

3 0

2 years ago

Does anyone know this?

Stels [109]

Every hexagon clearly has 6 sides. Nevertheless, every time you "glue" two hexagons together, you "lose" 2 sides to your count, because the sides where the two hexagons meet are not exterior sides anymore, and so they are not taken into account in our counting.

Also observe that with n hexagons you have n-1 points of contact between hexagons.

Since every hexagon has 6 sides and every gluing point takes away 2 sides, the number of exterior sides with n hexagons is

$s(n)=6n - 2(n-1) = 6n-2n+2=4n+2$

Let's plug some values for n:

$s(1) = 4\cdot 1 + 2 = 4+2 = 6$
$s(2) = 4\cdot 2 + 2 = 8+2 = 10$
$s(3) = 4\cdot 3 + 2 = 12+2 = 14$
$s(4) = 4\cdot 4 + 2 = 16+2 = 18$

You can check that these values are correct by counting the sides on the figure you have.

Finally, we can count the sides of a train with 10 hexagons by plugging n=10 in our formula:

$s(10) = 4\cdot 10 + 2 = 40 + 2 = 42$

Note: the numbers we've given are the number of sides that form the perimeter. So, the actual perimeters are the number of sides multiplied by the length of the side itself: if we let $s$ be the length of the side, the perimeters will be $6s,\ 10s,\ 14s,\ 18s$ for the first 4 trains, and $42s$ for the 10-hexagon train.