Answer:
13
Step-by-step explanation:
a parallelogram has sides that are parallel to the opposite side. This means that y + 7 is going to be parallel to 20.
Two opposing sides of a parallelogram are parallel and equal
You know that the length of both of the sides is equivalent because the other set of opposing lines is also parallel (you can think of it as cutting off the line segment of y+7 and 20 at the same length. )
this means that we can set up the equation to find y as:
y + 7 = 20
then, you can proceed to find y by isolating it:
y + 7 = 20 ; so therefore
y + 7 = 20
- 7 -7
y = 13
y = 13
So, the value of y is 13
Answer:
10.50 acres per hour or 1.75 per 10 minutes(1/6 of an hour)
Step-by-step explanation:
5/6 of an hour is 50 minutes
1/6 of an hour is 10 minutes
8 3/4 is equal to 8.75
8.75/5 is equal to 1.75 which means she harvests 1.75 acres per hour
1.75 x 6(hour) is equal to 10.50 acres total in one hour
Answer:
7 1/2+ 7 1/2=146 of 146 Kerry and Eric ran the same amount each
Answer:
D
Step-by-step explanation:
According to remainder theorem, you can know the remainder of these polynomials if you plug in x = -6 into them.
<em>So we will plug in -6 into x of all the polynomials ( A through D) and see which one equals -3.</em>
<em />
<em>For A:</em>
For B:
For C:
For D:
The only function that has a remainder of -3 when divided by x + 6 is the fourth one, answer choice D.
Answer:
45 girls
Step-by-step explanation:
- Remark
- There are only 2 choices for gender. So if the class is 60% girls, the there must be 100 - 60 = 40% for the boys.
- But we are told that the boys are 30 in number.
- Let x = the total number of students.
Solution
- 40/100 * x = 30 Change the % to a decimal
- 0.4 x = 30 Divide both sides by 0.4
- 0.4 x / 0.4 = 30 / 0.4 Do the division
- x = 30/0.4
- x = 75 students in total
Formula
Total of Boys and Girls = Number of boys + number of girls.
Givens
- Total = 75
- Number of boys = 30
Solution II
- 75 = x + 30 Subtract 30 from each side
- 75 - 30 = x +30 - 30
- 45 = x
- There are 45 girls in the class.
