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Vlad1618 [11]
3 years ago
9

Matt charges 3$ for every 15$of walking . how much will matt charge for one hour

Mathematics
2 answers:
IRINA_888 [86]3 years ago
8 0
5 dollars per hour
because 15 divided by 3 is 5.
svlad2 [7]3 years ago
8 0
Assuming you meant to say Matt charges $3 for every 15 minutes of walking. 60 / 15 = 4 | 4(3) $12 for one hour
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7x + 3 = 5 and y - 1= 6
Marina CMI [18]

Answer:

first answer is x= -5 second answer is y=7.

Step-by-step explanation:

7-5=2. 2+3=5.

7-1=6.

6 0
4 years ago
A rickshaw company counted 39 ticket receipts last week. The price for a weekday ticket is $7, and the price for a weekend ticke
Mademuasel [1]

Answer:

x+y = 39 and 14y+19=666

Step-by-step explanation:

Let x is the no of tickets for the weekend and y for the weekday.

The price for a weekday ticket is $7, and the price for a weekend ticket is $9.50. The rickshaw driver collected a total of $333 for the week.

Equation (1) should be :

x+y = 39 (because a rickshaw company counted 39 ticket receipts last week)

Equation (b) should be :

7y+9.5=333

Multiplying both sides by 2.

14y+19=666

Hence, the two equations that represent the situation are :

x+y = 39 and 14y+19=666

3 0
3 years ago
While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem
Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = <em><u>population proportion</u></em>.

So, Null Hypothesis, H_0 : p = 0.013      {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, H_A : p > 0.013      {means that this is an unusually high number of faulty modems}

The test statistics that would be used here <u>One-sample z-test</u> for proportions;

                             T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~  N(0,1)

where, \hat p = sample proportion faulty modems= \frac{10}{367} = 0.027

           n = sample of modems = 367

So, <u><em>the test statistics</em></u>  =  \frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }

                                     =  2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. <u>Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.</u>

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0
4 years ago
The area of a rectangle is x^2-4/2x in.^2 and its length is (x+2)^2/2 in. What is the width in inches?
Over [174]
Is b I’m sure check
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3 years ago
50 POINTS !!<br><br><br> PLEASE HELP !! ILL GIVE BRAINLIEST TO THE RIGHT ANSWERS.
nata0808 [166]
(Btw that’s not 50 points, imma solve this for you because you’re desperate)

Using the Pythagorean theorem:
c^2 = a^2 + b^2
c^2 = 4^2 + 7^2
c^2 = 16 + 49
c^2 = 65
c = 8.1
5 0
3 years ago
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