Question

A home is to be built on a 61 foot 6 inches wide lot. The house is 7 feet 2 inches from the side of the lot and is 41 foot 6 inches wide.How far is the house from the other side of the lot?

Answer 1

I belive the answer is 12 feet and 10 inches from the other side of the lot
:)

Answer 2

Answer: The house is 12 feet 10 inches far from the other side of the lot .

Step-by-step explanation:

Since we have given that

Size of a home  = 61 foot 6 inches wide lot

We first convert it into inches,

so, we get,

$61\times 12+6=738\ inches=a$

Size of the house from the side of the lot = 7 feet 2 inches

So, it becomes

$7\times 12+2=84+2=86\ inches=b$

So, We get,

$a-b=738-86=652=c\ inches$

Now, we have,

Width of the house = 41 foot 6 inches

So, it becomes

$41\times 12+6=498\ inches=d$

So, house is far from the other side of the lot is given as

$c-d=652-498=154\ inches$

Hence, The house is 154 inches far from the other side of the lot .

i.e.

$\frac{154}{12}=12\ feet\ 10\ inches$