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Maslowich
3 years ago
9

Help me with this plz

Mathematics
1 answer:
djyliett [7]3 years ago
7 0
Ok what do u need help with?

You might be interested in
Pls help I really need it
tangare [24]

Answer:

x = 20

p =54

y= 54

Step-by-step explanation:

2x-4 = 96-3x

5x = 100

x = 20

2x-4 = 40-4 = 36

(180 - (36 x 2))/2

(180-72)/2

108/2

p = y =54

5 0
3 years ago
Isabel began training for a marathon by running 63 miles during her first week. Each week, she increased the distance she ran by
Ulleksa [173]

Answer:

10% of 63 is 6.3 so 63+6.3=69.3

Step-by-step explanation:

7 0
3 years ago
The two triangles are similar What is the value of x? Enter your answer in the box x =
lilavasa [31]

Answ x=59

Step-by-step explanation:

4 0
2 years ago
Brice has $1200 in the bank. He wants to save a total of $3000 by depositing $40 per week from his paycheck. Write and use an eq
Anon25 [30]

$$3000-$1200=$1800

take $1800÷$40=45

<h3>answ=45 weeks</h3>

6 0
3 years ago
Un submarino se encuentra 50m por debajo del nivel del mar y comienza a subir 2m cada 5 minutos ¿a que profundidad se encuentra
Trava [24]

Answer:

a) El submarino se encuentra a una profundidad de 26 metros una hora después de haber comenzado el ascenso.

b) Al submarino le falta 1 hora y 5 minutos para llegar a la superficie.

Step-by-step explanation:

a) De acuerdo con el enunciado, la cantidad de metros ascendidos por el submarino es directamente proporcional al tiempo, entonces la profundidad del submarino a la hora de haber comenzado el ascenso se obtiene mediante la siguiente relación lineal:

h = 50\,m - \frac{2\,m}{5\,min}\times 60\,min

h = 26\,m

El submarino se encuentra a una profundidad de 26 metros una hora después de haber comenzado el ascenso.

b) En primer lugar, calculamos el tiempo total del viaje mediante la siguiente relación:

\frac{2\,m}{5\,min} = \frac{50\,m}{t}

t = 50\,m\times \frac{5\,min}{2\,m}

t = 125\,min (2\,h\,5\,min)

El tiempo faltante para alcanzar la superficie se calcula mediante la siguiente sustracción:

\Delta t = 125\,min - 60\,min

\Delta t = 65\,min (1\,h\,5\,min)

Al submarino le falta 1 hora y 5 minutos para llegar a la superficie.

7 0
3 years ago
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