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son4ous [18]
3 years ago
9

To estimate a population mean, the sample size needed to provide a margin of error of 3 or less with a 95% confidence when the p

opulation standard deviation equals 11 is
(Round your answer to the nearest integer.)

Mathematics
1 answer:
Over [174]3 years ago
7 0

Answer:

The minimum sample needed to provide a margin of error of 3 or less is 52.

Step-by-step explanation:

The confidence interval for population mean (<em>μ</em>) is:

\bar x\pm z_{\alpha /2}\frac{\sigma}{\sqrt{n}}

The margin of error is:

MOE= z_{\alpha /2}\frac{\sigma}{\sqrt{n}}

<u>Given:</u>

MOE = 3

<em>σ </em>= 11

The critical value for 95% confidence interval is: z_{\alpha /2}=1.96

**Use the <em>z</em>-table for critical values.

Compute the sample size (<em>n</em>) as follows:

MOE= z_{\alpha /2}\frac{\sigma}{\sqrt{n}}\\3=1.96\times \frac{11}{\sqrt{n}}\\n=(\frac{1.96\times11}{3} )^{2}\\=51.65\\\approx52

Thus, the minimum sample needed to provide a margin of error of 3 or less is 52.

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