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3 years ago

Zero is _____ a divisor. a.always b.sometimes c.never

Mathematics

1 answer:

ASHA 777 [7]3 years ago

5 0

ANSWER

c. never

EXPLANATION

When we have

$\frac{a}{b}$ in mathematics, we call b the divisor.

In mathematics, division by zero is not defined.

We cannot divide a function, or a number by zero and get a value.

That is why, there is the restriction, b≠0

Therefore, zero is never a divisor.

The correct answer is C

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A company that packages salted and unsalted mixed nuts received a complaint that claimed that the company’s salted packages cont

Eduardwww [97]

Answer:

$H_0 : \mu_1 - \mu_2 = 0$

$H_a : \mu_1 - \mu_2 \ne 0$

Step-by-step explanation:

Let the salted package be represented with 1 and the unsalted, 2.

So:

$\mu_1:$ Mean of salted package

$\mu_2:$ Mean of unsalted package

Considering the given options, the null hypothesis is that which contains =.

So, the null hypothesis is:

$H_0 : \mu_1 - \mu_2 = 0$

The opposite of = is $\ne$ . So, the alternate hypothesis, is that which contains $\ne$

So, the alternate hypothesis is:

$H_a : \mu_1 - \mu_2 \ne 0$

4 0

2 years ago

Find the fifth term in the sequence that is defined as follows:

hram777 [196]

Answer : The fifth term in the sequence is -2.

Step-by-step explanation :

As we are given that the expression to calculate the $n^{th}$ term.

The expression is as follows:

$a_n=2(-1)^n$

where,

n is the number of term

Given:

n = 5

Now putting the value of n in the above expression, we get:

$a_n=2(-1)^n$

$a_5=2(-1)^5$

$a_5=2\times (-1)$

$a_5=-2$

Therefore, the fifth term in the sequence is -2.

5 0

2 years ago

Which of these has a sum of 1 19/30 ?

nata0808 [166]

<h3>Answer:</h3>

4/5+5/6

Step-by-step explanation:

4/5+5/6=1 19/30

not

49/16+49/14
24/17+25/13
98/45+98/15

hope this helps u

3 0

3 years ago

Read 2 more answers

PLEASE HELP ME!!!!!!!!!!!!

o-na [289]

<h2>The correct Answer is:</h2><h2>C. = 16</h2>

6 0

3 years ago

What are the solutions of 3d-<-10or 2d+7>9?

Natali5045456 [20]

$3d < -10\ \vee\ 2d+7 > 9\\\\(1)\qquad3d < -10\ \ \ \ |:3\\.\qquad \qquad d < -\dfrac{10}{3}\\\\(2)\qquad2d+7 > 9\ \ \ \ |-7\\.\qquad\qquad2d > 2\ \ \ \ |:2\\.\qquad\qquad d > 1\\\\Answer:\ d < -\dfrac{10}{3}\ \vee\ d > 1\to d\in\left(-\infty,\ -\dfrac{10}{3}\right)\ \cup\ (1,\ \infty)$

3 0

2 years ago