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e-lub [12.9K]
3 years ago
15

The length of a rectangle is 4 meters less then twice its width. the area of the rectangle is 70 meters squared. Find the width

of the rectangle
Mathematics
1 answer:
Travka [436]3 years ago
8 0

Answer:

yes es correcto ya que 70 es igual a 4 metros

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M/9+2/3=7/3<br><br> Solve for m.
Aleks04 [339]
<span>M/9+2/3=7/3
</span><span>M/9 =7/3 - 2/3
M/9 = 5/3
M = 5/3 x 9
M = 15</span>
3 0
3 years ago
A tennis ball machine serves a ball vertically into the air from a height of 2 feet, with an initial speed of 120 feet per secon
Makovka662 [10]

Answer:

The maximum height is reached after 3.75 seconds.

Step-by-step explanation:

Assuming the deceleration due to gravity is unaided by air resistance, gravity causes the ball to lose vertical speed at the rate of 32 ft/s every second. The initial vertical speed of 120 ft/s will decline to zero when t satisfies ...

... 120 ft/s - (32 ft/s²)t = 0

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6 0
3 years ago
Destiny and Guadalupe are shopping. Destiny buys 2 pairs of pants and 6 bracelets and pays $178.Guadalupe buys 3 pairs of pants
ziro4ka [17]

For the entirety of this problem, p will represent a pair of pants and b will represent a bracelet.

Step 1) Set up equations for Destiny and Guadalupe

Destiny: 178 = 2p + 6b

Guadalupe: 155 = 3p + 2b

I will be using substitution to solve this problem, but elimination can also be used.

Step 2) Solve Destiny's equation for p

178 = 2p + 6b

178 - 6b = 2p

89 - 3b = p

Step 3) Substitute the found value of p from Destiny's equation into Guadalupe's equation and solve for b

155 = 3(89 - 3b) + 2b

155 = 267 - 9b + 2b

155 = 267 - 7b

-7b = -112

b = 16

Step 4) Use the value of b found in step 3, plug that back into our equation from step 2 and solve for p

89 - 3(16) = p

89 - 48 = p

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one bracelet = $41

Hope this helps!! :)

4 0
3 years ago
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Irina18 [472]

Answer:

see explanation

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(a)

2x + 10 ← factor out 2 from each term

= 2(x + 5)

(b)

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(c)

8x + 6 ← factor out 2 from each term

= 2(4x + 3)

(d)

12x - 8 ← factor out 4 from each term

= 4(3x - 2)

5 0
2 years ago
Suppose a figure is located in Quadrant I. Which of the following sequences will result in an image that is located in Quadrant
vladimir2022 [97]
The answer that results in an image located in Quadrant II is <span>C. rotate 90 degrees counterclockwise, then shift 1 unit up. This is because Quadrant II is located next (at the left) of Quadrant I. This means that a 90 degree rotation and a shift up are safe enough to estimate it to land on Quadrant II.</span>
4 0
3 years ago
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