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3 years ago

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A farmer has rights to pump 1,500 gallons of water a minute from a river that runs through his property. He uses 0.9

1 answer:

Tju [1.3M]3 years ago

6 0

The rate at which he pumps water is $\frac{1500gal}{min}$ .
To find the number of hours it takes to pump 0.9 million gallons, we can set a proportion.
$\frac{1500gal}{min} = \frac{0.9*100000}{x} \\ \\ 1500x = 0.9*1000000 \\ x = 900000/1500 = 600min$ .
The question asks for the time in hours, so convert 600 min to hours. One hour is 60 min.
$600min* \frac{hr}{60min} = 10hr$

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Solve the system of equations algebraically.

nordsb [41]

Answer: D

Step-by-step explanation:

$4x-3y=8\\5x-4y=5$

Let's take one of the equations and solve for a variable to use the substitution method.

$5x-4y=5\\5x=5+4y\\x=\frac{5+4y}{5}$

Now replace this in the first equation.

$4x-3y=8\\4(\frac{5+4y}{5})-3y=8\\\frac{20+16y}{5}-3y=8$

Separate the terms.

$\frac{20}{5}+\frac{16y}{5}-3y=8$

Solve 20/5

$4+\frac{16y}{5}-3y=8$

Subtract 4 from both sides to isolate y.

$4-4+\frac{16y}{5}-3y=8-4$

$\frac{16}{5}y-3y=4$

Solve the difference.

$\frac{16-(3)(5)}{5}y=4\\$

$\frac{16-15}{5} y=4$

$\frac{1}{5}y=4$

Multiply by the reciprocal or the inverted fraction that is next to y to isolate it.

$(\frac{5}{1} )(\frac{1}{5})y=4(\frac{5}{1})$

$y=20$

Now, in order to find x, replace y in any of the two equations.

$5x-4y=5\\5x-4(20)=5\\5x-80=5\\5x=5+80\\5x=85\\x=\frac{85}{5}\\x=17$

7 0

3 years ago

Help me and can you put the equation you used

mezya [45]

Answer:

3.45652173913

Step-by-step explanation:

the equation is 159 divided by 46

6 0

4 years ago

Any help would be nice

Mashutka [201]

Answer:

$18.75

Step-by-step explanation:

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3 years ago

Read 2 more answers

Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

Andre45 [30]

Answer:

Option d) 5 to the power of negative 5 over 6 is correct.

$\dfrac{\sqrt[3]{\bf 5} \times \sqrt{\bf 5}}{\sqrt[3]{\bf 5^{\bf 5}}}= 5^{\frac{\bf -5}{\bf 6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

ie, $5^\frac{\bf -5}{\bf 6}$

Step-by-step explanation:

Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

It can be written as below

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}} \times 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{5^5}= 5^{\frac{-5}{6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

7 0

4 years ago

A road construction crew is resurfacing the highway between point d and e. The distance between point d and e is 93 miles of roa

Ulleksa [173]

93 - 35 = 58
58/2.9 = 20
it will take them 20 more days.

3 0

3 years ago