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murzikaleks [220]
3 years ago
6

Please help me i will give you brainlist i really need help

Mathematics
1 answer:
tangare [24]3 years ago
4 0

Answer:

x = 5, y = 15

Step-by-step explanation:

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I need help please! I've been stuck on this for a week and its really stressful lol
worty [1.4K]

Answer:

y=0.2*4^{x}

Step-by-step explanation:

Notice when x increases 1, y is 4 times the previous one, so

the function is like y=C*4^{x}

To determine the constant C, put any pair of (x, y)

Use x = 0, y = 0.2, so

0.2 = C*4^{0} = C * 1 = C

then y=0.2*4^{x}

5 0
3 years ago
Read 2 more answers
Two Customers took out car loans from a bank.
padilas [110]
10,000(1+(0.047*5))=12350
Marcus-12350

10,000(1+(0.045*6))=12,700
Gianna-12,700

12,700-12,350=$350 difference
6 0
3 years ago
Picture attached please help!
Aleonysh [2.5K]
The answer is 12.56.

I just used the area of circle formula

The formula is 3.14 x r^2

2 x 2 is 4

4 x 3.14 is 12.56


Pls mark brainleist
3 0
3 years ago
Besties pls help!!!!<br><br> 8) In the diagram below, what is the m measure of R.
Dafna1 [17]

Let's see what we can fill in here.

<ACE = 130

180 - 50 = 130

Now that we have two sides and an included angle, we can use the Law of Cosines.

Law of Cosines: c^2 = a^2 + b^2 - 2ab(cos(C))

Let's plug in what we know and solve!

c^2 = 40^2 + 38^2 - 2(40)(38)(cos(130))

R = 70.69706

Hope this helps!! :)

4 0
3 years ago
Read 2 more answers
Find Mx, My, and (x, y) for the lamina of uniform density rho bounded by the graphs of the equations. y = x2/3, y = 0, x = 1
erik [133]

Answer:

\mathbf{(\overline x , \overline y ) = (\dfrac{5}{8},  \dfrac{5}{14})}

Step-by-step explanation:

Given that:

y =  x^{2/3} at y = 0 , x = 1

Then:

Area = \int^{1}_{0} x^{2/3} \ dx

Area = \begin {bmatrix} \dfrac{3}{5}x^{5/3} \end {bmatrix} ^1_0

Area = \dfrac{3}{5}

Then:

\overline x = \dfrac{1}{A} \int^b_a x (f(x) -g(x) ) \ dx

\overline x = \dfrac{5}{3} \int^1_0 x (x^{2/3} -0 ) \ dx

\overline x = \dfrac{5}{3} \int^1_0 x^{5/3} \ dx

\overline x = \dfrac{5}{3} \ [\dfrac{3}{8}x^{8/3}]^1_0

\overline x = \dfrac{5}{3} \times \dfrac{3}{8}

\overline x = \dfrac{5}{8}

Similarly;

\overline y = \dfrac{1}{A} \int^b_a \dfrac{1}{2} \begin{bmatrix} (f(x)^)2 - (g(x))^2 \end {bmatrix}  \ dx

\overline y = \dfrac{5}{3} \int^1_0 \dfrac{1}{2} \begin{bmatrix} (f(x^{2/3})^2 -0 \end {bmatrix}  \ dx

\overline y = \dfrac{5}{3} \int^1_0 \dfrac{1}{2} \begin{bmatrix} (x^{4/3} ) \end {bmatrix}  \ dx

\overline y = \dfrac{5}{3} \begin{bmatrix} \dfrac{1}{2}  (x^{7/3} ) \times \dfrac{3}{7} \end {bmatrix} ^1_0

\overline y = \dfrac{5}{3} \begin{bmatrix} \dfrac{3}{14}  (x^{7/3} ) \end {bmatrix} ^1_0

\overline y = (\dfrac{5}{3} \times \dfrac{3}{14} )

\overline y = \dfrac{5}{14}

Thus; \mathbf{(\overline x , \overline y ) = (\dfrac{5}{8},  \dfrac{5}{14})}

4 0
3 years ago
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