2-2n=3n+17
2= 5n+17
0= 5n+15
-15= 5n
-3= n
Answer:
By the Central Limit Theorem, both would be approximately normal and have the same mean. The difference is in the standard deviation, since as the sample size increases, the standard deviation decreases. So the SRS of 600 would have a smaller standard deviation than the SRS of 200.
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean
and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For the sampling distribution of size n of a sample proportion p, the mean is p and the standard deviation is 
Differences between SRS of 200 and of 600
By the Central Limit Theorem, both would be approximately normal and have the same mean. The difference is in the standard deviation, since as the sample size increases, the standard deviation decreases. So the SRS of 600 would have a smaller standard deviation than the SRS of 200.
7.5 min per walk around the block
Answer:
450 people paid the discounted fare and 750 people paid the regular fare.
Step-by-step explanation:
let r be regular fares paid and d be discounted fares paid
Total fares = 0.8r + 0.4d = 780
Since 1200 people paid the fares,
r + d = 1200 = Total people
Rearrange this formula:
r = 1200 - d
Substitute r into Total Fares formula
Total fares = 0.8r + 0.4d
780 = 0.8(1200-d) + 0.4d
780 = 960 - 0.8d + 0.4d
780 = 960 - 0.4d
0.4d = 180
d = 450
Sub d=450 into Total people formula
r + d = 1200 = Total people
r + 450 = 1200
r = 1200-450
r = 750
450 people paid the discounted fare and 750 people paid the regular fare.