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mart [117]
3 years ago
10

In a class in which the final course grade depends entirely on the average of four equally weighted 100-point tests, Joyce has s

cored 85, 83, and 86 on the first three. What range of scores on the fourth test will give Joyce a B for the semester (an average between 80 and 89, inclusive)?
Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
8 0

Answer:

66 ≤ f ≤100

Explanation

Mean= ( Σ x ) / n

Mean= sum of scores/ number of subject she took

Now, she already too 3 subject which sum is 85+83+86=254

Now we need to know range of score for her to have (grade) a mark between 80 and 89

Now let take the lower limit mean=80

The lowest score she can get is

Mean = ( Σx) / n

80=(85+83+86+f)/4

80×4= 254+f

Therefore, f= 320-254=66

Therefore the minimum score she can have to have a B is 66.

Then, let take the upper limit mean 89. i.e the maximum she can have so that she don't have an A grade.

Mean = ( Σx) / n

89=( 83+85+86+f)/4

89×4= 254+f

f= 356-254

f=102.

Therefore this shows that she cannot have an A grade in the exam. The maximum score for the exam is 100.

There the range of score is 66 ≤ f ≤100 to have a B grade

66 ≤ f ≤100 answer

Since she cannot score 102 in the examination.

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Answer:

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Step-by-step explanation:

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3 years ago
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Delicious77 [7]

Answer:

Function:

c = f(w) = 0.49, 0 < w ≤ 1

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            = 0.91, 2 < w ≤ 3

Step-by-step explanation:

Yes, the relation described can be interpreted as a function.

Here, c is the cost of a mail letter. c depends upon w, which is the weights of the mail letter.

As described in the question, the relation can be expressed as a function.

c can be expressed as a function of w in the following manner:

c(cost of mail) = f(w), where w is the independent variable and c is the dependent variable

c = f(w) = 0.49, 0 < w ≤ 1

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            = 0.91, 2 < w ≤ 3

where, c is in dollars and w is in ounces.

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