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atroni [7]
3 years ago
6

To receive a grade of A on an 80-question test, 90% of the questions must be answered correctly. What is the maximum number of q

uestions that can be missed to still receive an A?
Mathematics
1 answer:
marta [7]3 years ago
8 0

Answer:

The answer would be 8.

Step-by-step explanation:

This is a percentage question, and I have struggled with these before but this is the <em>easiest</em> way to solve it given these certain criteria.

Alright, so it's given that:

A) 90%= an A grade

and

B) This is an 80-question test.

Given these, we can do the following:

90% times 80, which equals <em>72</em>.

Just to check, we know that to convert percentages to fractions, we move the decimal two spots to the left, therefore 90%= 0.90, or 0.9. We take 72 and divide it by 80, and we get 0.9, thus showing that it is correct.

Then, we do 80-72 and using simple math we get 8.

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Rewrite the equation C = 3.59q + 54,293 as a function of q.
MAVERICK [17]

The equation, when rewritten would be written as:    

q = ( c - 54293 ) / 3.59

<h3>How to rewrite the equation in order to make q the subject</h3>

C = 3.59q + 54,293

We have the equation above, what we would have to do now would be to write the equation in such a way that q would be the subject of the formula.

This would be

3.59q = C -  54,293

Next we have to divide through by the value of q

q = \frac{C - 54293 }{3.59}

Read more on subject of formula here: brainly.com/question/21140562

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1 year ago
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Answer:

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Step-by-step explanation:

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3 years ago
A food packet is dropped from a helicopter and is modeled by the function f(x) = −15x2 + 6000. The graph below shows the height
melisa1 [442]

General Idea:

Domain of a function means the values of x which will give a DEFINED output for the function.

Applying the concept:

Given that the x represent the time in seconds, f(x) represent the height of food packet.

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x\geq 0

The height of the food packet cannot be a negative value, so

f(x)\geq 0

We need to replace -15x^2+6000 for f(x) in the above inequality to find the domain.

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The possible solutions of the above inequality are given by the intervals (-\infty , -2], [-2,2], [2,\infty ). We need to pick test point from each possible solution interval and check whether that test point make the inequality (x+200)(x-200)\leq 0 true. Only the test point from the solution interval [-200, 200] make the inequality true.

The values of x which will make the above inequality TRUE is -200\leq x\leq 200

But we already know x should be positive, because time cannot be negative.

Conclusion:

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