Question 5, x could be either 6 or -1.
Solution :
Given :

1. Cumulative distribution function




![$=\frac{1}{450}\left[\frac{x^3}{3}-\frac{x^2}{2}\right]_6^x$](https://tex.z-dn.net/?f=%24%3D%5Cfrac%7B1%7D%7B450%7D%5Cleft%5B%5Cfrac%7Bx%5E3%7D%7B3%7D-%5Cfrac%7Bx%5E2%7D%7B2%7D%5Cright%5D_6%5Ex%24)
![$=\frac{1}{450}\left[ \left( \frac{x^3}{3} - \frac{x^2}{2}\left) - \left( \frac{6^3}{3} - \frac{6^2}{2} \right) \right] $](https://tex.z-dn.net/?f=%24%3D%5Cfrac%7B1%7D%7B450%7D%5Cleft%5B%20%5Cleft%28%20%5Cfrac%7Bx%5E3%7D%7B3%7D%20-%20%5Cfrac%7Bx%5E2%7D%7B2%7D%5Cleft%29%20-%20%5Cleft%28%20%5Cfrac%7B6%5E3%7D%7B3%7D%20-%20%5Cfrac%7B6%5E2%7D%7B2%7D%20%5Cright%29%20%5Cright%5D%20%20%24)
![$=\frac{1}{450}\left[\frac{x^3}{3} - \frac{x^2}{2} - 54 \right]$](https://tex.z-dn.net/?f=%24%3D%5Cfrac%7B1%7D%7B450%7D%5Cleft%5B%5Cfrac%7Bx%5E3%7D%7B3%7D%20-%20%5Cfrac%7Bx%5E2%7D%7B2%7D%20-%2054%20%5Cright%5D%24)
2. Mean 


![$=\frac{1}{450} \left[\frac{x^4}{4} - \frac{x^3}{3} \right]_6^{12} \ dx$](https://tex.z-dn.net/?f=%24%3D%5Cfrac%7B1%7D%7B450%7D%20%5Cleft%5B%5Cfrac%7Bx%5E4%7D%7B4%7D%20-%20%5Cfrac%7Bx%5E3%7D%7B3%7D%20%5Cright%5D_6%5E%7B12%7D%20%5C%20dx%24)

![$=\frac{1}{450} [4608 - 252]$](https://tex.z-dn.net/?f=%24%3D%5Cfrac%7B1%7D%7B450%7D%20%5B4608%20-%20252%5D%24)
= 17.2857
Answer:
The slope is 2
Step-by-step explanation:
The slope, when given two points, is found from
m = (y2-y1)/(x2-x1)
= (15--5)/(3--7)
= (15+5)/(3+7)
=20/10
=2
False.
6(x)+434=?
x= number of hours so problem can be rewritten as
6(37)+434
———
222+434=
656