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Dennis_Churaev [7]
3 years ago
14

An automobile with 0.279 m radius tires travels 65000 km before wearing them out. How many revolutions do the tires make, neglec

ting any backing up and any change in radius due to wear? (You do not need to enter any units.)
Mathematics
1 answer:
bija089 [108]3 years ago
7 0

Answer:

Revolutions=37079108.61 rev

Step-by-step explanation:

First if all we have to make the units same to calculate the revolutions

Since distance gis gien in km and radius is given in m we will covert distance to m first.

Distance =S=65000km

Distance=S=65000km*1000m/km

Distance = S= 65000000m

Formula:

S=rθ

where

S is the distance

r is the radius

θ is the revolution in radian

θ=S/r

θ=65000000/0.279

θ=232974910.4 rad

Revolutions=θ/2π

Revolutions=232974910.4/2π

Revolutions=37079108.61 rev

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Anna71 [15]

Answer:

5,18,12 cms are the answer.

Step-by-step explanation:

Given is a triangle ABC.  Point D is the centroid.  

E,F and G are midpoints of CB, BA and AC respectively.

AE, BF and CG are medians of the triangle.

We know that centroid divides the median in the ratio 2:1

Using this we find that AD:DE = 2:1

Or AD+DE:DE = (2+1):1

AE:DE =3:1

15:DE = 3:1 . Hence DE =5 cm.

On the similar grounds we find that DF = 1/3 BF = 9

Hence BD = DF-BF = 27-9 =18 cm

and also

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2 years ago
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X²+3x-21=0

1) we solve this square equation:
x=[-3⁺₋√(9+84)] / 2=(-3⁺₋√93)/2
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2) we compute the product of the 2 solutions found.
[(-3-√93)/2][(-3+√93)/2] =(-3-√93)(-3+√93) / 4=
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Answer:

Step-by-step explanation:

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a = b² = 36

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Step-by-step explanation:

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