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ZanzabumX [31]
3 years ago
15

What is the probability of choosing a number 1 - 10 that is greater than 5 or even?

Mathematics
1 answer:
matrenka [14]3 years ago
8 0

Answer:

70%

Step-by-step explanation:

So, first, our set of choices is 10. This means that there are 10 choices.

We want a number that is greater than 5 or even. Thus, let's mark down all of our choices.

Numbers greater than 5 are:

6, 7, 8, 9, and 10.

Even numbers are:

2, 4, 6, 8, 10.

However, we already counted 6, 8, and 10 previously, so we'll ignore that.

All in all, the following numbers will satisfy our requirements:

2, 4, 6, 7, 8, 9, and 10.

This is 7 out of 10 numbers.

Therefore, our probability is:

7/10=70\%

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Sophia exchanged 1000 U.S. dollars for the South African currency which is called the rand. The exchange rate was 8.05 rand to 1
saw5 [17]

Answer:

Sophia gets 7,150

Step-by-step explanation:

6 0
3 years ago
Find the equation of a line that is perpendicular to y = 3x – 5 and passes through the point (1, -3).
Svetradugi [14.3K]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

\begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad \qquad y = \stackrel{\stackrel{m}{\downarrow }}{3}x-5

well then therefore

\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{3\implies \cfrac{3}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{3}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{3}}}

so we're really looking for the equation of a line with slope of -1/3 and that passes through (1, -3 )

(\stackrel{x_1}{1}~,~\stackrel{y_1}{-3})\qquad \qquad \stackrel{slope}{m}\implies -\cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{-\cfrac{1}{3}}(x-\stackrel{x_1}{1})\implies y+3=-\cfrac{1}{3}x+\cfrac{1}{3} \\\\\\ y=-\cfrac{1}{3}x+\cfrac{1}{3}-3\implies y=-\cfrac{1}{3}x-\cfrac{8}{3}

6 0
2 years ago
If a position on the ocean floor is 12 kilometers below the sea level, which value describes the elevation of the ocean floor
LenKa [72]

Answer:

- 12

Step-by-step explanation:

The sea level serves as a reference point and may be used to describe objacetsvir positions above or below it. Therefore, the sea level is regarded as a zero point or level. Hence, objects below are describes to be at a negative distance while those above are assigned the positive sign. Hence, for a position which is 12 km below sea level, then the object is said to be at a distance of - 12 km (below sea level takes the negative sign.)

4 0
3 years ago
Allen is buying a video game that originally costs $49. He has a 10%-off
Annette [7]
The total amount Allen will need to pay for the video game is $48.96 as 49-0.1+0.06=48.96
7 0
4 years ago
Find the value for x. Round your answer to the nearest hundredth. Area of the triangle = 8 ft^2​
zmey [24]

Answer:

x = 3.51

Step-by-step explanation:

Since, formula to determine the area f a triangle is,

Area = \frac{1}{2}(\text{Base})(\text{Height})

     8 = \frac{1}{2}(x + 1)(3x - 7)

16 = x(3x - 7) + 1(3x - 7)

16 = 3x² - 7x + 3x - 7

16 = 3x² - 4x - 7

0 = 3x² - 4x - 23

3x²- 4x - 23 = 0

By quadratic formula,

x = \frac{-b\pm \sqrt{b^{2}-4ac}}{2a}

x = \frac{4\pm \sqrt{(-4)^{2}-4(3)(-23)}}{2(3)}

x = \frac{4\pm \sqrt{292}}{6}

x = \frac{4\pm 17.09}{6}

x = 3.51, -2.18

But the length of sides can't be negative.

Therefore, x = 3.51 will be the answer.

8 0
3 years ago
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