What is the probability of choosing a number 1 - 10 that is greater than 5 or even?
1 answer:
Answer:
70%
Step-by-step explanation:
So, first, our set of choices is 10. This means that there are 10 choices.
We want a number that is greater than 5 or even. Thus, let's mark down all of our choices.
Numbers greater than 5 are:
6, 7, 8, 9, and 10.
Even numbers are:
2, 4, 6, 8, 10.
However, we already counted 6, 8, and 10 previously, so we'll ignore that.
All in all, the following numbers will satisfy our requirements:
2, 4, 6, 7, 8, 9, and 10.
This is 7 out of 10 numbers.
Therefore, our probability is:
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Answer:
C. (5x - 1)(x + 8)
Step-by-step explanation:
In a factoring problem by hand, the common steps to solve would be the "AM" method, or (Add-Multiply). Simply stated, finding what adds to the x-coeficient and what multiplies to the constant. In this case, what adds to 39(x) and what multiplies to 8. Just reading that, we can see that there aren't any numbers that can do that, so we have to improvise. Set up the problem equal to something that it can factor into:
- <em>Multiply the 5 and -8</em> = -40: <em>this is what we will factor</em>
- <em>The factors with add to 39 are 40 and -1</em>.
- <em>Set up the problem:</em>
Now, we can fo the math:
8(5x - 1) + x(5x - 1)
<em>Factor (5x - 1) from this:</em>
(5x - 1)(x + 8)
And we have our answer.