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marin [14]
3 years ago
8

Maria invests $6,154 in a savings account with a fixed interest rate of 8% compounded continuously. What will the account balanc

e be after 10 years?
Mathematics
1 answer:
Vitek1552 [10]3 years ago
3 0

Answer:

$13,695.98

Step-by-step explanation:

We can use the continuous compound interest formula to solve:

A = Pe^{rt}

<em>P = principal amount</em>

<em>r = interest rate (decimal)</em>

<em>t = time (years)</em>

<em />

First, lets change 8% into a decimal:

8% -> \frac{8}{100} -> 0.08

Now, lets plug in the values:

A=6,154e^{0.08(10)}

A=13,695.98

The account balance after 10 years will be $13,695.98

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frozen [14]

Answer:

Step-by-step explanation:

Discussion

This should be answered with the mean. The lower the mean, the lower the  score it took to get the mean. So B is the answer.

4 0
2 years ago
Need help with number 4 and number 5
ivanzaharov [21]

Answer:

4. D

5. A

Step-by-step explanation:

For #4, I first divided 15 by 4 and saw what the greatest whole number it was divisiable by. Then I wrote the remain as a fraction

For #5, I first multiplied by 4*6 and then add 5 to that answer

7 0
2 years ago
Monthly sales of an SUV model are expected to increase at the rate of S′1t2 = -24t 1&gt;3 SUVs per month, where t is time in mon
uysha [10]

The company will continue to manufacture this model for 19 months.

The question is ill-formatted. The understandable format is given below.

An SUV model's monthly sales are anticipated to rise at a rate of

S'(t)=-24^{1/3} SUVs each month, where "t" denotes the number of months and "S(t)" denotes the monthly sales of SUVs. When monthly sales of 300 SUVs are reached, the business intends to discontinue producing this model.

Find S if monthly sales of SUVs are 1,200 at time t=0 (t). How long will the business keep making this model?

Given S'(t)=-24^{1/3} ... ... (1)

Condition (1) at t=0; s(t) =1200

We find S(t)=300 then t=?

a) We find S(t)

from S'(t)=-24^{1/3}

\implies \frac{dS(t)}{dt}=-24t^{1/3} ~~[\because X'(t)=\frac{dX}{dt} \\\implies dS(t) = -24t^{1/3}dt\\

On Integrating both sides

S(t)=-18t^{4/3}+c ~...~...~(2)

Now, at t=0 then S(t)=1200

So, from (2)

1200=0+c

⇒c=1200

\thereforefrom eq (2)

S(t)=-18t^{4/3}+1200 ~...~...~(3)

b) Considering that the firm intends to cease production of this model once monthly sales exceed 300 SUVs.

So, take S(t)=300

from eq (2) 300=-18t^{4/3}+1200

t^{4/3}=\frac{1200-300}{18}\\=\frac{900}{18}=50\\\implies t=50^{3/4}\\\implies t=18.8030

Hence the company will continue 18.8020 months.

Learn more about integration here-

brainly.com/question/18125359

#SPJ10

8 0
1 year ago
The number 0.6064 represents the area under the standard normal curve below a particular z-score. What is the Z-score? Express t
Anastasy [175]
P(z < x) = 0.6064 - 0.5 = 0.1064

From the normal distribution table
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Therefore the z-score is 0.27

I can't explain it very well for you, sorry. 
4 0
2 years ago
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What are the first and last deciles of the standard Normal distribution?
aliya0001 [1]

My best Guess is

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Hope this Helps

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