Construct the bisector of the following figures :
1 answer:
1. Draw an circle centred at B, using a radius that is
longer than half of the length of AB.
2. Using the same radius, draw an circle centred at A (and at C) to cut the previous circle.
3. Join points of intersection as shown in the picture. These two lines (PS and RS) are arc bisectors.
4. The point of intersection is a center of a circle which passes through points A,B,C.
2. Using the same radius, draw an circle centred at A (and at C) to cut the previous circle.
3. Join points of intersection as shown in the picture. These two lines (PS and RS) are arc bisectors.
4. The point of intersection is a center of a circle which passes through points A,B,C.
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Answer:
68.26% probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds
This is the pvalue of Z when X = 8.6 subtracted by the pvalue of Z when X = 6.4. So
X = 8.6
has a pvalue of 0.8413
X = 6.4
has a pvalue of 0.1587
0.8413 - 0.1587 = 0.6826
68.26% probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds