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vichka [17]
3 years ago
11

Study the graph carefully. Which of the following statements is true? The graph is drawn correctly. The titles are misleading. T

he intervals are not the same width. The graph does not start at 0. 

Mathematics
2 answers:
Trava [24]3 years ago
4 0
Its the 3rd one because none of them are the same
kumpel [21]3 years ago
4 0

The graph is depicting the relation between employees and the salaries.

These is a need to explain which statement is true.

Here, the correct answer is C. The intervals are not of same width.

As we can see, the intervals are starting from 0-19 showing a difference of 19, till the point 40-49 they are correct, but after 49, the next interval is 50 - 99, showing a difference of 49.

<u>Thus, the intervals are not of same width. </u>

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Write four equivalent expressions for 3(6m+3)
Vadim26 [7]
1st. 18m+9
2nd. 3(3+6m)
3rd. 9+18m
4th. 3(6m+3)
5 0
2 years ago
5.3.73 Question Help
Tatiana [17]

Area of the triangle is 20x(x - 1) sq. in

Step-by-step explanation:

  • Step 1: Find the area of the triangle.

Height = 10x in and Base = 4(x - 1) in

Area = 1/2 × base × height

⇒ Area = 1/2 × 4(x - 1) × 10x

            = 20x(x - 1) sq. in

6 0
3 years ago
If the point A (6,9) is translated 4 units left, then find the new coordinates of the point A.
Alex_Xolod [135]

Answer:

(2, 9 )

Step-by-step explanation:

A translation of 4 units left is equivalent to subtracting 4 from the value of the x- coordinate, that is

(6, 9 ) → (6 - 4, 9 ) → (2, 9 )

6 0
3 years ago
A company with 17 employees gives each employee a bonus of $459. How much does the company spend on bonuses?
Vlad1618 [11]

Answer: Option D: $7803

Step-by-step explanation:

just multiply 459 by 17 and you get your answer.

7 0
1 year ago
Help! How would I solve this trig identity?
NeTakaya

Using simpler trigonometric identities, the given identity was proven below.

<h3>How to solve the trigonometric identity?</h3>

Remember that:

sec(x) = \frac{1}{cos(x)} \\\\tan(x) = \frac{sin(x)}{cos(x)}

Then the identity can be rewritten as:

sec^4(x) - sen^2(x) = tan^4(x) + tan^2(x)\\\\\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)}  = \frac{sin^4(x)}{cos^4(x)}  + \frac{sin^2(x)}{cos^2(x)} \\\\

Now we can multiply both sides by cos⁴(x) to get:

\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)}  = \frac{sin^4(x)}{cos^4(x)}  + \frac{sin^2(x)}{cos^2(x)} \\\\\\\\cos^4(x)*(\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)}) = cos^4(x)*( \frac{sin^4(x)}{cos^4(x)}  + \frac{sin^2(x)}{cos^2(x)})\\\\1 - cos^2(x) = sin^4(x) + cos^2(x)*sin^2(x)\\\\1 - cos^2(x) = sin^2(x)*sin^2(x) + cos^2(x)*sin^2(x)

Now we can use the identity:

sin²(x) + cos²(x) = 1

1 - cos^2(x) = sin^2(x)*(sin^2(x) + cos^2(x)) = sin^2(x)\\\\1 = sin^2(x) + cos^2(x) = 1

Thus, the identity was proven.

If you want to learn more about trigonometric identities:

brainly.com/question/7331447

#SPJ1

7 0
1 year ago
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