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3 years ago

Solve the system by substitution. 6x + 3y = -6 2x + y = -2

2 answers:

8 0

Solutions

First Lets solve for this equation $6x + 3y = -6
$

$6x + 3y = -6
$

$6x+3(-2-2x)=-6

 
$

$-6=-6$

Therefore this given equation is a <span>dependent system.
</span>
<span>Solve for </span> $2x + y = -2$

$2x+y=-2$

$y=-2-2x

 

 
$

There are too many solutions to these equations.

Simora [160]3 years ago

5 0

6x + 3y = -6
2x + y = -2

Solve both equations for the same variable, in this case, I'll solve for y.

2x + y = -2 Subtract 2x from both sides
y = -2x -2

6x + 3y = -6 Subtract 6x from both sides
3y = -6x -6 Divide both sides by 3
y = -2x -2

Once you have them solved you can set them equal to each other and solve.

-2x -2 = -2x -2

But, these two equations are the same, so any number you put in for x will work. The answer to the system is infinite solutions.

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Suppose that the average and standard deviation of the fine for speeding on a particular highway are 111.12 and 13.04, respectiv

antoniya [11.8K]

Answer:

3) (98.08, 124.16)

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 111.12

Standard deviation = 13.04

Calculate an interval that is symmetric around the mean such that it contains approximately 68% of fines.

68% of the fines are within 1 standard deviation of the mean speed. So

From 111.12 - 13.04 = 98.08 to 111.12 + 13.04 = 124.16

The interval notation in the smallest value before the highest value.

So the correct answer is:

3) (98.08, 124.16)

8 0

3 years ago

Help please due in 20 minutes I will mark brainliest

navik [9.2K]

Answer:

its the second one down my dude. good luck!

6 0

3 years ago

Lim x-1 x³-2x²+3x-2/(2x^4-3x+1)

UkoKoshka [18]

Since the limit becomes the undetermined form

$\displaystyle \lim_{x\to 1} \dfrac{x^3-2x^2+3x-2}{2x^4-3x+1} \to \dfrac{0}{0}$

it means that both polynomials have a root at $x=1$ . So, we can fact both numerator and denominator:

$x^3-2x^2+3x-2 = (x-1)(x^2-x+2)$

$2x^4-3x+1 = (x-1)(2x^3+2x^2+2x-1)$

So, the fraction becomes

$\dfrac{(x-1)(x^2-x+2)}{(x-1)(2x^3+2x^2+2x-1)} = \dfrac{x^2-x+2}{2x^3+2x^2+2x-1}$

Now, as x approaches 1, you have no problems anymore:

$\displaystyle \lim_{x\to 1} \dfrac{x^2-x+2}{2x^3+2x^2+2x-1} \to \dfrac{2}{5}$

4 0

3 years ago

Tlachihualtepetl is a pyramid in Mexico. Each side of the base measures 450 meters and had an original height of 66 meters. How

LenKa [72]

Answer:

44,55,000 cubic meters of treasure could fit the pyramid.

Step-by-step explanation:

We are given the following in the question:

Base measure = 450 meters

Height = 66 meters

The volume of the pyramid is given by:

$V = \dfrac{AH}{3}$

where A is the ares of the base and H is the height of the pyramid.

Putting values, we get,

$V = \dfrac{1}{3}\times (450\times 450) \times 66\\\\V = 4455000\text{ cubic meters}$

Thus, 4455000 cubic meters of treasure could fit the pyramid.

8 0

3 years ago

Write an iterated integral for ModifyingBelow Integral from nothing to nothing Integral from nothing to nothing Integral from no

coldgirl [10]

With the given order of integration, the interval over D is

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8 0

3 years ago