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3 years ago

Write a real world problem that can be represented by the equation 3/4c =21

1 answer:

3 0

Hello!!

One possible answer:

"Nathan and Jake make a business deal. Nathan receives three quarters of the money made if he runs Jake's shop for a week. Nathan receives 21 dollars. What was the total amount of money made for that week?"

Hope this helps!! Let me know if you have ANY questions.

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Need Answer ASAP, help me please, offering 80 points.

Fed [463]

Hey there! Since these shows you must find the graph so finally the answers should be

1.The slope of 1/5

2.The slope of DC =2/3

3.The slope of AB= 1/4

4.The slope of DA=7/2

5. B. Yes the quadrilateral has two pairs of of opposites that are perpendicular and all of its interior angles are right angles.

Hope this helped.

7 0

3 years ago

Read 2 more answers

You are asked to do a study of shelters for abused and battered women to determine the necessary capacity in your city to provid

ohaa [14]

Answer:

Using the normal probability distribution, with a capacity of 350, it is enough for all abused on 90.82% of nights.

274 shelters will be needed.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 250, \sigma = 75$

If the city’s shelters have a capacity of 350, will that be enough places for abused women on 95% of all nights?

What is the percentile of 350?

This is the pvalue of Z when X = 350.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{250 - 150}{75}$

$Z = 1.33$

$Z = 1.33$ has a pvalue of 0.9082.

Using the normal probability distribution, with a capacity of 350, it is enough for all abused on 90.82% of nights.

If not, what number of shelter openings will be needed?

The 95th percentile, which is X when Z = 1.645. So

$Z = \frac{X - \mu}{\sigma}$

$1.645 = \frac{X - 150}{75}$

$X - 150 = 1.645*75$

$X = 274$

274 shelters will be needed.

5 0

2 years ago

Which system has no solution.

elena55 [62]

There is no picture with this so I don’t know how to answer this

3 0

3 years ago

In 1626, the Dutch bought Manhattan Island, now part of New York City, for $24 worth of merchandise. Suppose that, instead, $24

Radda [10]

2008 - 1626 -= 382

24 x (1.305)^382

= 12,229,955,10

Hope this helps

5 0

3 years ago

Read 2 more answers

Put a digit in the gap, such that the answer is a whole number:

Makovka662 [10]

Answer: The possible digits are 2,5 and 8

Step-by-step explanation:

3x +486 = 100_

From the equation in the question, we are looking for a digit to put in the gap after 100 to make sure that when we solve the question, x will be a whole number.

Therefore, since it's a single digit required, the possible digits will be from 0 to 9.

Now, from divisibilty tests, for a number from 2 digits upwards to be divisible by 3, the sum of its digits has to be divisible by 3.

Going back to the question, let's divide each term by 3 to get ;

3x/3 + 486/3 = 100_ to give ;

x + 162 = 100_ /3

Now for x to be a whole number, the value on the right hand side must be a whole number.

Therefore, since we know that for a 2 digits and above number to be divisible by 3,it's sum must be divisible by 3. We can plug in any of the digits from 0-9 into the gap and add up.

For 0; 1+0+0+0= 1

For 1; 1+0+0+1 = 2

For 2; 1+0+0+2= 3

Following the same addition pattern for digits 3,4,5,6,7,8and 9, we'll get sum of 4,5,6,7,8,9 and 10 respectively.

Inspecting the above, the only additions that are divisible by 3 are when the digit is; 2,5 and 8

6 0

3 years ago