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Anit [1.1K]
3 years ago
11

The table shows a linear relationship between x and y.

Mathematics
1 answer:
Mama L [17]3 years ago
6 0

Answer:

В:

X 3 9 15      

Y 4 16 20

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your test scores in one class are 76 and 84 what possible scores can you earn on your next test to have a test average between 8
Orlov [11]

you have to get a 80 i think

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4 years ago
What are the explicit equation and domain for an arithmetic sequence with a first term of 5 and a second term of 2?
xenn [34]
For the answer to the question above asking the explicit equation and domain for an arithmetic sequence with the first term of 5 and the second term of 2? I think the answer for this is <span>5-2(n-1); all integers where n≥0. I hope this helps.</span>

7 0
3 years ago
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Given the points below, are the two lines parallel, perpendicular, or neither?
Karo-lina-s [1.5K]

Answer:

none of them are perpendicular or parallel

5 0
3 years ago
Answer correct you get brainliest answer​
zloy xaker [14]

Answer:

y =  {x}^{2}  - 2

Or if you want with the value of h too.

y =  {(x - 0)}^{2}  - 2

Step-by-step explanation:

y = a {(x - h)}^{2}  + k

Find the value of h and k by using the formula.

h =  -  \frac{b}{2a}  \\ k =  \frac{4ac -  {b}^{2} }{4a}

From y = x²-2

a = 1 \\ b = 0 \\ c =  - 2

Substitute these values in the formula.

h =  -  \frac{0}{2(1)}  \\ h = 0

Therefore, h = 0.

k =  \frac{4(1)( - 2) -  {0}^{2} }{4(1)}  \\ k =  \frac{ - 8}{4}  \\ k =  - 2

Therefore, k = - 2.

From the vertex form, the vertex is at (h, k) = (0,-2). Substitute h = 0, a = 1 and k = -2 in the equation.

y = a {(x - h)}^{2}  + k \\ y = 1 {(x - 0)}^{2}  - 2 \\ y =  {(x)}^{2}  - 2 \\ y =  {x}^{2}  - 2

These type of equation where b = 0 can also be both standard and vertex form.

4 0
3 years ago
What is the least common denominator of<br> 5/12 and 3/8
borishaifa [10]
5/12 and 3/8 is the answer
4 0
3 years ago
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